Page 103 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

95
2.

ก "
ก V = I Z
d
o
out
(
- ก I = g V
d m
V = g VZ
o m out
(
- ก V =
E
i
V = g E Z
m i out
o
ก "
( " E =
V
i
V o (2.53)

$
A = − = − g Z
V (F Mid ) E i m out

E = I i ( R + Z in )
g
g
E g
I =
i
( R + Z in )
g
E Z
g in
E = I Z =
i
i in
( R + Z in )
g
E i = Z in
E ( R + Z )
g g in
V o V o E i Z in
A V (F Mid ) = − E g = − E i × E g = − g Z × ( R + Z in )
m out
g
V o V o Z in Z in

$
A V (F ) = − = − × = − g Z × (2.53a)
m out
Mid
E g E i ( R + Z in ) ( R + Z in )
g
g
V o V o
,
2.25 ก ,% 2.22 , A V (F Mid ) = − A V (F Mid ) = −
E
i E g
= −
V
o
- .
ก ก (2.53) A V (F )
Mid
E i
)
V o − 3
×
A = − = − g Z = − ( 2.217 10 × 947.368 = − 2.10
V (F Mid ) m out
E i
V o V o Z in Z in
ก ก (2.53a) A V (F ) = − = − × = − g Z ×
m out
Mid
E g E i ( R + Z in ) ( R + Z in )
g
g
×
V o 43.532 10 3
×
A = − = − 2.10× = − 2.10 0.998 = − 2.095
V (F Mid ) 3
×
+
E g ( 75 43.532 10 )
V o V o 2.095;
== =
= − −− −
= − −− −
== =
A V (F Mid ) == = E i = − −− − 2.10, A V (F Mid ) = − −− − E g == =
ก

ก
ก