Page 94 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

86
2.

2.1.5.9 ก

A V (F Mid ) , A V (F L ) (+# A V (F H )

V o g r Z g r Z
′
′
m b e out
m b e out
ก ก (2.10) A V (F Mid ) = − = − ) = −
r
E
i ( bb′ + r b e ′ Z i
V o g r Z Z in
′
m b e out
ก ก (2.11) A V (F Mid ) = − = − ×
E
g Z i R + Z in
g
V o
ก ก (2.16) A V (F L ) = − E g = 0.707A V (F Mid ) 45
V o
ก ก (2.18) A V (F ) = − = 0.707A V (F ) − 45
H
E g Mid
V o V o V o V o
,
2.18 ! A V (F Mid ) = − E i , A V (F Mid ) = − E g , A V (F L ) = − E g , A V (F H ) = − E g ;
V o g r Z
′
m b e out
- .
ก ก (2.10) A = − = −
V (F Mid )
E
i Z i
×
2.595 10 − 3
* % g = = 100.972 mS
m
×
25.7 10 − 3
β o 120 3
×
Ω
+
Ω
r b e ′ = = − = 1.188 k , Z = r bb′ + r b e ′ = ( 2 1.188 10 ) = 1.190 k ;
i
×
g m 100.972 10 3
+
×
Z = r bb′ + r b e ′ = ( 2 1.188 10 3 ) = 1.190 kΩ
i
×
3
×
R Z 10.183 10 × 1.190 10 3
Z = BB i ) = 3 3 = 1.065 kΩ
in
+
×
×
( R BB Z i ( 10.183 10 + 1.190 10 )
3
×
R R 1.6 10 × 75 71.641 Ω
C L
Z = R = = =
out out ( R + ) ( 3 )
×
C R L 1.6 10 + 75
×
3
×
V o 100.972 10 − 3 × 1.1833 10 × 71.641 7.193
A V (F Mid ) = − = − = −
×
E
i ( 1.190 10 3 )
×
V o 1.065 10 3
)
ก ก (2.11) A = − = − ( 7.193 ×
V (F Mid ) 3
×
+
E g ( 75 1.065 10 )
A V (F Mid ) = − ( 7.193 0.934× ) = − 6.718
V o
ก ก (2.16) A V (F ) = − = 0.707A V (F ) 45
L E g Mid
V o
A V (F ) = − = − (0.707 6.718× ) = − 4.749 45
L
E g
V o
ก ก (2.18) A V (F H ) = − E g = 0.707A V (F Mid ) − 45
ก

ก
ก