Page 33 - Pressure 10 class

Numericals based on ArchimedesPrinciple

2. Observe the given figure and answer the following questions;

i. How much is the weight of the body in air?

ii. Find out the mass of the stone .

iii. How much is the upthrust exerted ?

iv. Calculate the mass of the water displaced.

Solution: Given, Weight of stone in water(W1) = 20N

Weight of water displaced (W2)= 5N

i. Weight of stone in air = W1 + W2 = 20N + 5N = 25N

ii. Mass of stone ( m) = ?

We know that , Weight (W) = m x g

or, 25 = m x 9.8

or, 25 / 9.8 = m

or, m = 2.55kg

Therefore, mass of the stone is 2.55kg.

iii. Upthrust (U) = Weight of water displaced = 5N

iv. Mass of water displaced(m) = ?

Weight of water displaced(w) = 5N

Then Weight( W) = m x g ( Same as previous)

July 30, 2020 Taranath Baral/GC Shiba/Suraj Thapaliya 33