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© GC Shiba
                                                    
                               
                                       1
                                              1
                               1
        Then,    =    ( ) ( ) ( )
                          1
                  2
                                2        2      2
                                                1      1   1      1  1        −2
                                         = 5 (       ) (        ) (         )
                                                 1        1          1      


                                                1000       1  100        1
                                         = 5 (           ) (            ) × 1
                                                   1            1    


                                                              5
                                                  = 5 × 10         


     iv.  To determine the dimension of proportionality constant:
               The force of attraction between two bodies is separated by certain distance is

                                      
               given by    ∝       1  2
                                      2
                                            2
                                        1
                                =                ℎ                                                              .
                                          2

                                                                 2
                                              ,        =           … … … (  )
                                                                 2
                                                             1


               From above relation, we can say that dimension of                       2   is the dim. of G.
                                                                                       2
                                                                                   1

                                                                      0
                                                                          0 2
                                       ∴,    =        2  =  [       −2 ][        ]    = [   −1 3 −2 ]
                                                                                              
                                                      2           [  ] 2
                                                  1

        Limitations of dimensional analysis:
            ❖ Dimensionless constant can’t be determined by using dimensional analysis.
            ❖ Trigonometric and exponential relation can’t be derived using dimensional

               analysis.
            ❖ Dimensional analysis can’t be used if the physical quantity involves other

               quantities than mass, length and time.
            ❖ Dimensional analysis can’t be used to derive a relation if more than one term
               is involved.
            ❖ It never gives numerical values (it confined to MLT only).

            ❖ It never provides the information whether the given quantity is vector or
               scalar.





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