Page 27 - Pra U STPM 2021 Penggal 1 - Physics
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Physics Term 1  STPM  Chapter 2  Kinematics
                  (i)  Describe qualitatively the motion of       The total stopping distance is the sum of the
                      the trolley during the periods OA, AB   distance travelled by the vehicle during the
                      and BC.                                 reaction time of the driver and the distance
                  (ii)  Calculate the acceleration of the     travelled when the brakes are applied.
                                                                             x
                      trolley down the incline.               Draw a graph of   against v. Use the graph to
                  (iii)  Find the length of the incline.      find           v
                  (iv)  Calculate the distance the trolley    (a)  the total stopping distance if the velocity
       2              moved up the incline on the                of the vehicle is 35 m s .
                                                                                      –1
                      rebounce.                               (b)  the reaction time of the driver.
             15. The table below shows the total stopping
              distance  x for different velocities  v of a
              vehicle.

               v/m s –1  10.0  15.0  20.0  25.0  30.0

                 x/m    20.0   37.5  60.0  87.5 120.0














                ANSWERS



                       1                                    2.  22 m s –1
                                                                  2h
             1.  (a)  Use  v = u + at                       3.  g =   2  2
                                                                 t 2  – t 1
                  (i)   2.0 m s –1
                  (ii)  4.0 m s
                            –1
                  (iii)  10.0 m s –1                                  3
                                   1                        1.  C    2.  B    3.  C     4.  C     5.  A
              (b)  Use average speed =   (u + v)
                                   2                        6.  C    7.  C    8.  B     9.  C
                  (i)   1.0 m s –1
                  (ii)  2.0 m s –1                         10.  (a)      Displacement
                  (ii)  5.0 m s –1
              (c)  Use s = average speed × time
                  (i)   1.0 m         (ii)  4.0 m

                  (iii)  25.0 m
             2.  25 m                                                             Time
             3.  48 m s –1                                           0    t 1  t 2
                                                              (b)     Acceleration
                       2
             1.  (a)  Use v = u + at, t = 0.815 s
              (b)  Use v  = u  – 2gH                                             Time
                      2
                          2
                  H  = 3.26 m above the building.                    0    t 1  t 2
                    = 12.26 m from the ground
                            1
                                2
              (c)  Use s = uT –   gT  , s = –9.0 m
                            2
                  T = 2.40 s
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     02 STPM PHY T1.indd   56                                                                         4/9/18   8:19 AM
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