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Chemistry Term 1  STPM  Chapter 1 Atoms, Molecules and Stoichiometry
                Question 6

                  The following mass spectrum is obtained for an element X which exists as a
                  molecule X 2. X has two isotopes P and Q with relative atomic mass a and b.

                                Relative
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                                abundance
                                            4      28      49

                                           2a      a + b    2b m/e                     Term
                  What is the relative abundance of isotope P and Q?
                  A  1 : 2                       C  2 : 3                             1
                  B  1 : 3                       D  2 : 7


                Answer: D
                   Let the abundance ratio of P and Q is x : y.
                                                          y
                                                   x
                   Probability of obtaining P and Q is ——— : ———
                    m     +  a a                (x + y) (x + y)
                    — of X 2  :  P P = (a + a) = 2a
                    e
                                 x
                                         x
                                           
                                     
                               
                   Probability =  ——–    ×  ——–
                               x + y
                                       x + y
                    m     +  a b    b a                 Common Errors
                    — of X 2  :  P P or  P P = (a + b)
                    e
                                                          m
                                         x
                                 x
                                                           e
                                     
                               
                                           
                   Probability =  ——–    ×  ——–    × 2  For the — value of (a + b), students
                                                     did not multiply the relative
                                       x + y
                               x + y
                    m     +  b b                     abundance by two (There are two
                    — of X 2  :  P P = (b + b) = 2b
                                                     possible combinations of  P P and
                                                                        a b
                    e
                                         x
                                 x
                                                      a
                                     
                                           
                               
                   Probability =  ——–    ×  ——–      b P P.).
                                       x + y
                               x + y
                   From the diagram,
                                                x
                                        x
                      m
                                      
                                                   
                                            
                   at — 2a, probability =  ——–    ×  ——–    = 4
                                               x + y
                                       x + y
                      e
                                                    x
                                            x
                      m
                                                      
                                                
                                          
                   at — (a + b), probability =  ——–    ×  ——–    × 2 = 28
                                                  x + y
                      e
                                          x + y
                                        x
                                                x
                      m
                                      
                                            
                                                   
                   at — 2b, probability =  ——–    ×  ——–    = 49
                                       x + y
                                               x + y
                      e
                   Since the denominator is the same in all probabilities,
                   x  = 4 and y  = 49
                    2
                             2
                   Hence,
                                                 1
                                                 —
                   relative abundance of isotope P = (4)  = 2
                                                    2
                                                   1
                                                  —
                   relative abundance of isotope Q = (49)  = 7
                                                      2

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         01 STPM Q&A Chem T1 layout.indd   5                                   4/19/19   9:28 AM
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