Page 20 - Q & A STPM 2022 Chemistry
P. 20

Chemistry Term 1  STPM  Chapter 1 Atoms, Molecules and Stoichiometry
                         mass of 1 mol gas  m
                                            m
                   For A, ————–——–— = —– — = 2N A
                           mass of 1 atom  —––
                                           2N A
                          mass of 1 mol gas  m
                                             m
                   For B,  ————–——–—– = —–— = N A
                          mass of 1 molecule  —–
          Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
                                             N A
                          volume of 1 mol gas  V
                                              V
                   For C,  ————–——–—–– = —– — = 2N A
                            mass of 1 atom    —––
                                              2N A
                   For D, density of a substance does not depend on the number of particles.    Term
                                                                                      1
                   Section B    Structured Questions
                Question 8
                  A 100 cm  gaseous mixture of ethane, C 2 H 6  and butene C 4 H 8  is burnt in 500 cm   3
                          3
                  oxygen (excess) for complete combustion. After the mixture has been cooled,
                  the total volume of gas is 331 cm . Only 55 cm  of gas remains when the gaseous
                                            3
                                                      3
                  mixture is passed through concentrated NaOH solution.
                  (a)  Write two separate equations for the combustion of both gases.
                  (b)  Determine the volume of each gas in the mixture.


                Answer:
                                 7
                   (a)  C 2 H 6   +  —O 2   :  2CO 2   +  3H 2 O
                                 2
                       C 4 H 8   +  6O 2   :  4CO 2   +  4H 2 O
                   (b)  Assume that the volume of ethane gas = x cm ,
                                                            3
                       volume of butene gas = (100 – x) cm 3
                                     7
                       C 2 H 6    +   —O 2    :   2CO 2    +   3H 2 O
                                     2
                       x cm 3                     2x cm 3
                       C 4 H 8    +   6O 2    :   4CO 2    +   4H 2 O
                       (100 – x) cm   3        4(100 – x) cm 3
                       Since NaOH absorbs CO 2  gas (acidic), volume of excess, unreacted O 2
                       = 55 cm
                              3
                       Total volume of CO 2  formed  = 331 – 55 = 276 cm
                                                                3
                       Total volume of CO 2  formed  = 2x + 4(100 – x) = 276
                       Volume of C 2 H 6 , x = 62 cm 3
                       Volume of C 4 H 8  = 38 cm
                                           3





                                                15




         01 STPM Q&A Chem T1 layout.indd   15                                  4/19/19   9:28 AM
   15   16   17   18   19   20   21   22   23   24   25