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Mathematics Form 3 PT3 Model Paper Mathematics Form 3 PT3 Model Paper
11. Total time = 2345 – 2015 16. Mean Section B 0.5 cm
= 3.5 hours (12 × 5) + (15 × 3) + (18 × 7) + (21 × 2) 0.5 cm
250 + (24 × 6) 2
Average speed = = 21. (i) K = –2.4 = –2
3.5 5 + 3 + 7 + 2 + 6 5
4
= 71.43 km/h 417 L = –1.8 = –1
= 5
Answer: B 23
= 18 .13 (ii) KL – 1.203
= –2.4 (–1.8) – 1.203
Answer: A
12. (Cos 60° + sin 45°)(Cos 60° – sin 45°) = 4.32 – 1.203
2
2
1 + 1 – 17. Percentage of students weight more than = 3.117
2
2
2
2
= – 1 60 kg. 22. (a) (i) Line KM / Garis KM
4 = 25 + 5 × 100% (ii) Line AC / Garis AC
Answer: D 15 + 30 + 10 + 15 + 25 + 5 (b) 6 – 3y 4y – 8
= 30%
6 + 8 4y + 3y
13. Price after discount Answer: D 14 7y
25. (i) ✓
80
P = RM60 × = RM48 y 2
100 18. The interest Vadivoo has to pay (ii) ✗
5.85
75 = RM55 000 × × 2
Q = RM78 × = RM58.50 100 23. (a) Centre (b) (i) FALSE
100 = RM6 435 (b) Chord (ii) TRUE
95 (c) Major sector
R = RM53 × = RM50.35 Answer: B
100 (d) Circumference Section C
60
S = RM94 × = RM56.40 19. Answer: A 1 1
100 24. (a) Scale = 2 cm : 10 cm 26. (a) (i) =
3
64
4
= 1 : 5
∴ The cheapest type of diaper is diaper P 2 2
20. K(0, y) J(–2, 6) (ii) 2 – 9 = 2 – 3
1
Answer: A (b) AB = 36 × = 6 cm 3 3
Gradient JK = 3 6 7 2
y – 6 1 = –
= 3 BC = EF = 21 × = 3.5 cm 3
14. ∠UQP = ∠TSQ = 65° 0 – (–2) 1 6 49
y – 6 = 6 DE = 9 × = 1.5 cm =
∠QUP = 180° – 65° – 72° y = 12 6 9
1
= 43° AH = 42 × = 7 cm
∴ OK = 12 units 6
Answer: C x 2 –5 x –3 1
2
HE = AB × 1 (b) (i) 8y 2 × x = 8y 2 = 8x y
3 2
2
OL = 13 – 12 2 3 6
2 1 = 5 units 2 1 1
15. Probability of green dresses = 1 – – = (36) × = 4 cm 2
5 5 ∴ L(5, 0) 3 6 (ii) 9 3k – 1 = 729 × 81
2 3 –2
= 3 6k – 2 × 3 = 3 × 3 2
–2
6
5 x-intercept of KL is 5
3 6k – 4 = 3 8
2 Answer: C
× Total dresses = 10
5 ∴ 6k – 4 = 8
Total dresses = 10 × 5 6k = 12
2 k = 2
= 25 pieces
Answer: A
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BOOKLET ANS MATH F3.indd 30 03/01/2020 10:21 AM
