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–1
                            2
                            2
                   7.   1  8 x  + 3  + 3 = 52                        11.  (a)  Let f (x) = y
                                                                              3y
                                                                                   = x
                               2
                               2
                         1 8 x   + 3  = 49                                   y + 1
                                                                               3y  = xy + x
                           x
 =  1                      8  + 3 = 7                                         3y – xy  = x
                                                                            y(3 – x)  = x
 2                             x = 2                                                  x
 = √3                                                       [3]                 y  =   3 – x
                                                                                      x
 2
 2
                                                                              –1
 =  1  8 x   + 3      8.  a(ax + b) + b = 49x – 40                           f (x)  =   3 – x                [3]
                        a x + ab + b = 49x – 40
                        2
                       2
 =                    a x = 49x                                        (b)  x = 3
                        Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
 =                       a = 7  or  a = −7 (rejected)                                                        [1]
                       ab + b = –40                                  12.  (a)  Let f (x) = y
                                                                              –1
                         8b = –40                                             f(y) = x
                          b = –5                                             5 – 2y = x
                                                            [3]                2y = 5 – x
                    9.  Let y = f(x)                                            y =   5 – x
                      Let f (x) = z                                                  2
                          –1
                        f(z)  = x                                            f (x) =   5 – x
                                                                              –1
                         x  = 3 – z                                                  2
                                2
                         z   = 3 – x                                        f (–3) =   5 – (–3)
                          2
                                                                             –1
                          z  = √3 – x                                                  2
                      f (x)  = √3 – x                                       f (–3) = 4
                                                                             –1
                       –1
                                                                                                             [2]
                           y                                           (b)    gf(x) = 5(5 – 2x)
                          3                                                        = 25 – 10x
                                 y = f(x)                                   [gf(x)]  =   25 – x
                                                                                 –1
                                                                                      10
                                                                          (gf) (–5) =   25 – (–5)
                                                                             –1
                                                                                       10
                                                                                   = 3
                                               –1
                                            y = f (x)                                                        [3]
                                                                     13.  a(1 – 3x)  + b = a(1 – 6x + 9x ) + b
                                                                              2
                                                                                              2
                                                   x                              = a – 6ax + 9ax  + b
                                                                                              2
                                               3
                                                                       9a = 1
                                                            [5]          a =  1
                                                                           9
                    10.  (a)  2k – 1 = 0                                a + b = 6
                            2k  = 1                                       b = 6 –  1
                             k  =  1                                            9
                                 2                          [1]             =  53
                      (b)  (i)  gf(x) =   x + 3 – 1                           9                              [4]
                                    2(x + 3) – 1                     14.  (a)
                                 =   x + 2                                       y
                                   2x + 6 – 1
                                 =  x + 2
                                    2x + 5                  [2]
                         (ii)  fg(x) =   x – 1   + 3                            2
                                    2x – 1
                                 =  x – 1 + 3(2x – 1)
                                        2x – 1
                                 =  x – 1 + 6x – 3                              0   2     2           x
                                       2x – 1                                       3
                                    7x – 4
                                 =
                                    2x – 1
                                                            [2]

                                                                                                             [3]
                         Cambridge IGCSE
                                          TM
                  166     Ace Your Additional Mathematics





                                                         =  1
         Answers Add Math.indd   166                       2                                                     14/03/2022   12:29 PM
                                                         = √3
                                                                2
                                                                2
                                                         =  1 8  + 3
                                                           x
                                                         =
                                                         =
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