Page 25 - PRAKTIS HEBAT ADDMATHS TG4

Additional Mathematics Form 4 Answers
1
2
32. n = –3 (c) (i) 10— (ii) 16— unit 2
33. x + y + 4x – 10y + 13 = 0 3 3
2
2
34. x + 3y – 2 = 0 1
35. 3x + 3y – 4x + 38y – 13 = 0 14. (a) y = – —x + 7 (b) (18, –2)
2
2
2
36. 3x + 3y + 16x + 34y – 1 = 0 22 10
2
2
2
37. 11x – 7y – 35 = 0 (c) 1 —, — (d) 4
3
3
38. Locus of point P/ Lokus bagi titik P: 2 2 2
65
x + y – 6x + 4y – 51 = 0 15. (a) (x + 2) + (y – 5) = (AB )
2
2
x + 4x + 4 + y – 10y + 25 = 65
2
2
When/ Apabila y = 0, x – 6x – 51 = 0 2 2
2
b – 4ac = (–6) – 4(1)(–51) = 240 . 0 x + y + 4x – 10y – 36 = 0 [shown]
2
2
\ intersects with the x-axis (b) 1 27 41 2
—, — , (2, –2)
menyilang paksi-x [shown] 5 5
39. When/ Apabila y = 0, x + 5x + 28 = 0 16. (a) (–10, –2) (b) 60 unit 2
2
2
b – 4ac = (5) – 4(1)(28) = –87 , 0
2
\ does not intersect with the x-axis
tidak menyilang paksi-x [shown] HOTS PRACTICES PAK-21
40. a = 6, b = 14, c = 22 1. (a) (4, 2) (b) y = x – 2
41. t = –1, t = –4 (c) 3
2
42. (m – 1)x + (m – 1)y – (6m + 8)x + 16y + 9m (d) PRT : 2 unit , RTQ : 4 unit , PTS : 2 unit ,
2
2
2
2
2
2
2
2
– 80 = 0 QTS : 4 unit ,
2
(e) 12 unit 2
PAPER 2 (f) x + y – 8x – 4y – 80 = 0
2
2
7
2
2
1. (a) 14 unit 2 (b) 1 0, — 2 2. (a) x + y – 16x – 16y – 497 = 0
3
2
2
(c) 3x + 3y – 72x + 34y + 251 = 0 (b) y = 3x – 16
(c) (15.9, 31.7), (0.1, –15.7)
1
2. (a) y = – —x – 10
2
9
(b) (i) (0, –5) (ii) 1 —, 4 2 Pract ice
3. (a) m = 1, n = 2 2 8 Vectors
(b) m × m = –1 × 1 = –1 spm Vektor
BC BD
\ /CBD = 90°, hence can form a right-angled
triangle. / maka dapat membentuk sebuah segi PAPER 1
tiga bersudut tegak. 1. (a) scalar quantity because does not have direction
4. (a) 5 kuantiti skalar kerana tidak mempunyai arah
(b) (i) 3 : 2 (b) vector quantity because has magnitude and
2
2
(ii) 5x + 5y – 2x – 46y + 74 = 0 direction
24
3
5. (a) (i) (–8, 0) (ii) y = – —x – — kuantiti vektor kerana mempunyai magnitud dan
5
5
(iii) 96 unit 2 arah
(b) 3x + 3y – 8x + 72y = 0 2. (a) (b)
2
2
6. (a) y = –3x + 26 (b) (6, 8) 40 km h –1 Q 50 N P
(c) –1 (d) 10 unit 2 v ~ 40 km j –1
7. (a) x + y – 12x – 12y + 67 = 0
2
2
(b) n = 5, n = 7 (c) (10, –2) 3. (a), (b)
8. (a) (i) 126 m 2 (ii) (–1, 2)
(b) x + y – 8x – 14y + 56 = 0 Q
2
2
9. (a) 9x + 5y + 2 = 0
(b) (i) (–3, 5) 1 →
→
(ii) Both the roads do not pass through Pantai P –2PQ –PQ
2
Indah. / Kedua-dua jalan raya itu tidak
melalui Pantai Indah.
2 31 9
2
10. (a) y = —x + — (b) 1 3, —
5 5 2 4. (a) parallel/ selari (b) parallel/ selari
(c) 24 unit 2
→
→
2
2
(d) x + y – 12x + 6y + 20 = 0 5. ST = –6RS
3 → →
11. (a) y = —x – 7 (b) (2, –4) RS and ST are parallel, S is a common point, then R,
2
(c) 36 unit (d) 8 S and T are collinear.
2
→
→
12. (a) 3x + 3y – 52x – 58y + 311 = 0 RS dan ST adalah selari, S ialah titik sepunya, maka
2
2
R, S dan T adalah segaris. [shown]
(b) does not intersect with the y-axis
tidak menyilang paksi-y 6. m = 2, n = –3
→
→
43
1
13. (a) y = 3x – 9 (b) y = – —x + — 7. PQ = 6MN
3 3 8. (a) m = 2, n = 4 (b) m = 5, n = –4
© Penerbitan Pelangi Sdn. Bhd. A12