Page 19 - Syok Praktis PBD (2023) Mathematics TH5

ANSWERS

Pratice 16. (a) 30 000
(b) 137 850 + 29 600 = 167 450

1 Whole Numbers and Operations (c) 2 × (137 850 + 167 450) = 2 × 305 300
= 610 600
Objective Questions
1. B 2. D 3. D 4. D 5. B Pratice 2 Fractions, Decimals and Percentages
6. C 7. B 8. A 9. A 10. C
11. C 12. B 13. C 14. C 15. D
16. C 17. C 18. C 19. D 20. A Objective Questions
21. A 22. D 23. A 24. C 25. C
26. D 27. B 28. D 29. B 30. A 1. D 2. D 3. B 4. B 5. B
31. C 32. C 33. C 34. A 35. D 6. C 7. B 8. D 9. B 10. C
36. A 37. D 11. A 12. C 13. D 14. C 15. A
16. A 17. C 18. B 19. C 20. C
Subjective Questions 21. B 22. B 23. C 24. D 25. C
26. A 27. D 28. C 29. B 30. C
1. (a) 203 468
(b) Two hundred three thousand four hundred and Subjective Questions
sixty-eight 3 1 3 1
2. (a) 9 000 1. (a) 5 × = 10 (b) 2 × 200 = 100
2
(b) 3 hundred thousands + 1 ten thousands + 2. (a) 3.63
9 thousands + 2 hundreds + 4 tens + 5 ones
3. (a) 2, 3, 5 (b) 4, 6, 9 (b) 3.625 kg + 3.625 kg − 1.9 kg = 5.35 kg
4. (a) 300 000 3. (a) 130% (b) 1 3
(b) 299 123 (accept other answers) 10
5. (a) 142 665 (b) 142 680 4. (a) 30% × 560 stamps = 168 stamps
6. (a) ascending by tens (b) 70% × 560 stamps = 392 stamps
(b) 195 340
7. (a) 1 542 packets of sugar HOTS Practice
(b) 257 packets of sugar
1
1
1. Cookies given to Daim = × 5 kg
HOTS Practice 2 4
5
= 2 kg
1. 152 000 boxes of juice 8
2. (a) Quantity of Sinovac vaccines = (641 250 – 37 000) ÷ 2 The remaining cookies that Daim is not eaten
5
5
= 604 250 ÷ 2 = × 2 kg
= 302 125 7 7 8
(b) True. Quantity of Pfizer vaccines = 302 125 + 37 000 = 1 kg
8
= 339 125 1.57 m
2. Haikal
Summative Practice 1 Wong 1.69 m
Kumar
1. D 2. C 3. B 4. B 5. D The difference between the jumps of Haikal and Kumar
6. C 7. B 8. A 9. A 10. C = 1.57 m + 1.69 m
11. B = 3.26 m
12. (a) 460 000 3. Volume of the chemical solution 100%
(b) 491 035, 481 035, 471 035, 461 035 Volume of water 350% 900 ml
13. (a) 943 320 (b) 2 and 3
14. (a) Brand P 450% → 900 ml
(b) 164 925 + 120 376 + 145 088 + 159 324 = 589 713 1% → 900 ml ÷ 450 = 2 ml
15. (a) Three hundred twenty nine thousand seven Volume of water = 350 × 2 ml
hundred and eight = 700 ml
(b) 3 hundred thousands + 2 ten thousands + Volume of the chemical solution = 100 × 2 ml
9 thousands + 7 hundreds + 0 tens + 8 ones = 200 ml
(c) 349 708
A1 © Penerbitan Pelangi Sdn. Bhd.

10 Ans Syok! Maths Year5.indd 1 13/10/2022 1:41 PM