Page 23 - PBD Plus Matematik T1 (EG)

Matematik Tingkatan 1 Bab 1 Nombor Nisbah
Jawapan / Answer : Jawapan / Answer:
Y = [–8 – (–16)] ÷ 2 + (–16) 18.5 l adalah nilai yang paling rendah.
= 4 – 16 Maka, jus oren yang dijual paling sedikit
= –12 Nilai bagi satu bahagian ialah pada minggu 4.
senggatan
X = –16 – 4 – 4 18.5 l is the lowest value. Hence, the least orange
= –24 juice sold is in week 4.
Z = –8 + 4 + 4
= 0 (ii) Harga jus oren ialah RM0.80 bagi setiap
100 ml. Hitung jumlah hasil jualan jus
oren dalam tempoh 5 minggu. SP 1.4.4
Penerbitan Pelangi Sdn. Bhd.
 2
(ii) Hitung 1.2 × – 1 + 0.59. Ungkapkan The price of orange juice is RM0.80 for each 100 ml.
Calculate the total sales of orange juice in the
3
jawapan dalam nombor perpuluhan. 5 weeks. [3 markah / 3 marks]
 2
Calculate 1.2 × – 1 + 0.59. Express the answer Jawapan / Answer :
3
as a decimal. Jumlah isi padu jus oren yang dijual
[2 markah / 2 marks] Total volume of orange juice sold
Jawapan / Answer : = 43.3 + 29.4 + 38.3 + 18.5 + 24.6
 2
1.2 × – 1 + 0.59 = 154.1 l
3
Jumlah hasil jualan / Total sales
 2
= 6 5 × – 1 + 0.59 = (154.1 × 1 000) × 0.8
3
= –0.4 + 0.59 = 154 100 × 0.8 100
= 0.19 100
= 1 541 × 0.8
= RM1 232.80
11. (a) (i) Susun semula integer-integer berikut (c) Jadual di bawah menunjukkan suhu bagi
mengikut tertib menaik.
Rearrange the following integers in ascending empat jenis larutan, R, S, T dan V.
order. The table below shows the temperatures of four different
types of solutions, R, S, T and V.
10, –11, –2, 7, 20, 5, –1
Larutan / Solution Temperature / Suhu (°C)
[1 markah / 1 mark] R –6
Jawapan / Answer :
–11, –2, –1, 5, 7, 10, 20 S 4
T –5
V –9
(ii) Cari julat bagi integer di soalan(a)(i).
Find the range of the integer in (a)(i). (i) Nyatakan dua jenis larutan yang
[1 markah / 1 mark] manakah mempunyai beza suhu yang
Jawapan / Answer : terkecil. SP 1.2.1
20 – (–11) = 31 State two types of solutions that have the smallest
difference in temperature.
[2 markah / 2 marks]
(b) Rajah di bawah menunjukkan isi padu jus Jawapan / Answer :
oren yang dijual oleh Puan Aisyah dalam Larutan R dan T / Solution R and T
tempoh lima minggu di gerainya.
The diagram below shows the volumes of orange juice Beza suhu / Difference in temperature = 1°C
sold by Puan Aisyah in five weeks at her stall.
(ii) Tentukan tiga jenis larutan yang hasil

tambah suhunya ialah –11°C. SP 1.2.1
43.3l 29.4l 38.3l 18.5l 24.6l Determine three types of solutions that have a sum
of temperature of –11°C.
Minggu 1 Minggu 2 Minggu 3 Minggu 4 Minggu 5 [2 markah / 2 marks]
Week 1 Week 2 Week 3 Week 4 Week 5
(i) Nyatakan minggu yang jus oren dijual Jawapan / Answer :
Larutan R, S dan V / Solution R, S and V
adalah paling sedikit. SP 1.4.4
State the week that has the least orange juice sold. Jumlah suhu / Total temperature
[1 markah / 1 mark] = –6 + 4 + (–9) = –11°C

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