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Mathematics Semester 3  STPM  Chapter 2 Probability

                          Summary


                    1.  Addition principle of counting:
                       Let A , A , … A  be disjoint events with n , n , … n  possible outcomes, respectively.
                               2
                            1
                                                             2
                                                                  k
                                    k
                                                          1
                       Then the total number of outcomes for the event “A  or A  or … or A ” is n  + n  + … + n .
                                                                  1    2         k    1    2       k
                    2.  Multiplication principle of counting:
                       Let A , A , …, A  be events with n , n , …, n  possible outcomes, respectively.
                                                      2
                               2
                            1
                                                            k
                                     k
                                                    1
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                       Then the total number of outcomes for the sequence of these k events is
                                                         n  × n  × … × n
                                                          1    2       k
                    3.  First permutation rule                                                               2

                       The number of permutation of n distinct elements is n!.
                    4.  Second permutation rule
                                                                                          n!
                       The number of permutations of n distinct elements taken r at a time is,  P  =  (n – r)! .
                                                                                   n
                                                                                     r
                    5.  The number of distinct permutations of n elements of which n  are of one kind, n  of a second kind,
                                                                                           2
                                                                           1
                                                                n!
                       …, n  of a kth kind is given by the formula  n ! n ! … n ! .
                           k
                                                                2
                                                                     k
                                                             1
                    6.  The number of possible combinations of choosing r elements from a set of n elements without regard
                                         n!
                                 n
                       to order is,  C  =  (n – r)! r! .
                                   r
                    7.  An outcome is a result of some activity.
                       For example: Rolling a dice has six outcomes: 1, 2, 3, 4, 5, 6
                    8.  In statistics the word experiment is used to describe any process that generates raw data or outcome.
                    9.  A sample space is a set of all possible outcomes for an activity and is represented by S.
                       For example: The sample space for rolling a dice is, S = {1, 2, 3, 4, 5, 6}.
                   10.  An event is the collection of outcomes of particular interest in an experiment.
                   11.  An event is the subset of the sample space S.
                   12.  Probability is a measure of how likely an event is to happen.
                                          P(Event) =   number of ways that an event can occur
                                                       total number of possible outcomes
                   13.  (a)   The probability that an event will happen is between 0 and 1 inclusive, i.e.
                                                             0 < P(E) < 1
                       (b)  P(φ) = 0; φ is 0 collections.
                       (c)  P(S) = 1

                   14.  If an experiment can result in any one of N different equally likely outcomes, and if exactly n of these
                       outcomes correspond to event E, then the probability of event E is P(E) =   n  .
                                                                                     N

                   15.  If an experiment is repeated n times under the identical condition and an event is observed to happen
                       f times, the probability of the event happening is then estimated to be
                                                    frequency of the event occured  f
                                              P(E) =                            =
                                                     total number of observations  n


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         02 STPM Math(T) T3.indd   107                                                                28/10/2021   10:21 AM
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