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(c) (1, 2) –7 + y
(3.5, –0.5) [4] 3 2 = 1
(d) –6 to –7 [3] −7 + y = 2
(e) x – 6x + 7 ≤ 2x y = 9 [2]
2
x – 6x + 7
2
≤ 2 10 – 0
x 4 (a) m = –7 – 1
y ≤ 0 10
1 ≤ x ≤ 7 [2] = –8
2
(f) 2x – 17x + 14 = 0 5
2 = – 4
x – 17 x + 7 = 0 5
2
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2 10 = – (–7) + c
x – 6x – 5 x + 7 = 0 4
2
2 c = 5
5 4
x – 6x + 7 = x
2
2 y = mx + c
x – 6x + 7 5 5 5
2
= y = – x +
x 2 4 4
5 4y + 5x = 5 [3]
y =
2 (b) m = –1 ÷ – 5
x = 0.9 to 1 4 4
x = 7.5 to 7.6 [5] = 5 [2]
5 (a) 25, 30, 30, 25 [4] 5 (5, 0)
(b) (0, –3)
y 0 – (–3) 3
m = =
5 – 0 5
35 3
Penerbitan Pelangi Sdn Bhd.
y = x – 3 [3]
30
6 0 = 3 x – 5
25 5
x = 3
20
Q(3, 0)
15 P(–6, 0)
5
10 0 = ( ) (–6) + c
3
5 c = 10
0 x y = 5 x + 10
1 2 3 4 5 6 7 8 3
3y – 5x = 30
[5] a = 3
(c) 34 metres [1] b = –5
(d) 1 metre [1] c = 30 [4]
(e) –1 ± 0.05 [3] 5 – 3 k – 5
7 (a) =
4 – (–1) 9 – 4
3 3 Coordinate Geometry 2 = k – 5
5
5
k = 10 + 5
Coordinate geometry 5
k = 7 [3]
–7 – (–1)
1 Gradient = (b) m = 2
–2 – (–7) 5
6
= – [2] 5 = 2 (4) + c
5 5
2 Distance between AB = √(0 – 6) + (1 – 9) 2 17
2
= √36 + 64 c = 5
= 10 units [3] 2 17
y = x + [3]
5 5
Cambridge IGCSE
TM
166 Ace Your Mathematics
Answers.indd 166 15/03/2022 11:08 AM

