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6 1 3
2 1 5 2 (b) (i) × = [1]
(d) × + × 14 10 70
7 6 7 6 (ii) 1 – ( 6 × 2 + 6 × 7 + 6 × 1 )
= 1 + 5 14 10 14 10 14 10
21 21 4
= 2 [2] = 7 [2]
7 3 7 5 2 6 2 6 7
2 1 (iii) × + × + × + ×
(e) = [2] 14 10 14 10 14 10 14 10
6 3 = 17 [3]
(f) 2 = 1 28
n – 1 6 1
n – 1 = 12 13 (a) (i) 6 [1]
n = 13 [2] (ii) 4 = 2
( 14 13 12 ) 6 3 [1]
10 (a) 1 – 26 × 25 × 24 (iii) 0 [1]
) (
)
= 43 [2] (b) (i) ( 3 × 2 × 2 + 3 × 1 × 2 +
50
( 14 13 12 ) 21 6 6 6 6
(b) 26 × 25 × 24 × 3 = 50 [2] ( 2 1 )
( 14 13 12 ) ( 12 11 14 ) 6 × 6 × 2
(c) 26 × 25 × 24 × 3 + 26 × 25 × 24 × 3 = 12 + 6 + 4
= 21 + 231 36 36 36
50 650 = 11 [3]
)
) (
= 252 [3] 3 18 2 3 1
325 (ii) ( × × 2 + × × 2 +
11 (a) (i) 2 [1] 6 5 6 5
8 ( 2 × 1 × 2 )
(ii) 7 [1] 6 12 5 6 4
8
( 1 1 ) = 30 + 30 + 30
(b) (i) 8 × 8 × 5 11
=
5
15
=
[2]
Penerbitan Pelangi Sdn Bhd. All Rights Reserved. [3]
4
2
3
64
( 1 1 ) (c) 6 × 5 × 4
(ii) 8 × 8 × 12 = 1 [2]
= 3 [2] 5
16 130 13
12 (a) 14 (a) (i) 180 = 18 [1]
Box A Box B 35 7
3 (ii) 180 = 36 [1]
10 Red (b) 35 × 34
130 129
= 119 [2]
7 Black 1677
3 Red 10 (c) (i) 45 × 44 = 99 [2]
14 5 2 140 139 973
95
45
45
95
14 Black 10 Red (ii) 140 × 139 + 140 × 139
855
6 = 1946 [3]
14 White 8 Black 7 6 6 7 2
10 15 × x – 1 + x × x – 1 = 5
x
42 42 2
2 x(x – 1) + x(x – 1) = 5
10 Red 84 2
=
x(x – 1) 5
Black 2
7 x – x – 210 = 0
1 10 x = 15 or x = −14 (invalid) [4]
10
White
[5]
Cambridge IGCSE
TM
180 Ace Your Mathematics
Answers.indd 180 15/03/2022 11:08 AM

