Page 60 - ACE YR IGCSE A TOP APPR' TO MATHS
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6   1   3
                          2    1   5   2                               (b)  (i)    ×    =                    [1]
                      (d)    ×    +    ×                                      14  10   70
                          7    6   7   6                                  (ii)  1 –  (  6   ×   2   +   6   ×   7   +   6   ×   1 )
                          =  1   +   5                                            14  10  14   10  14  10
                            21  21                                              4
                          =  2                              [2]               =  7                           [2]
                            7                                                  3   7   5    2   6   2    6   7
                          2    1                                          (iii)   ×    +    ×    +    ×    +    ×
                      (e)    =                              [2]               14  10   14  10  14   10  14  10
                          6    3                                              =  17                          [3]
                      (f)    2   =   1                                          28
                          n – 1   6                                            1
                           n – 1 = 12                              13  (a)  (i)   6                          [1]
                              n = 13                        [2]           (ii)  4   =   2
                             ( 14  13  12 )                                    6   3                         [1]
                  10  (a)  1 –   26  ×  25  ×  24                         (iii) 0                            [1]
                                                                                        ) (
                                                                                                     )
                          =  43                             [2]        (b)  (i)   (  3   ×   2   × 2  +   3   ×   1   × 2  +
                            50
                          ( 14  13  12 )   21                                  6    6       6    6
                      (b)   26  ×  25  ×  24   × 3 =  50    [2]               (  2  1   )
                          ( 14  13  12 )   ( 12  11  14 )                      6   ×   6   × 2
                      (c)   26  ×  25  ×  24   × 3 +   26  ×  25  ×  24   × 3      =  12  +   6   +   4

                          =  21  +  231                                         36  36  36
                            50  650                                           =  11                          [3]
                                                                                                     )
                                                                                        ) (
                          =  252                            [3]                3 18  2      3    1
                            325                                           (ii) (   ×    × 2  +    ×    × 2  +
                  11  (a)  (i)   2                          [1]                6    5       6    5
                              8                                               (  2   ×   1   × 2 )
                         (ii)  7                            [1]                6 12  5 6  4
                              8
                             (  1  1 )                                        =  30  +  30  +  30
                      (b)  (i)   8   ×   8   × 5                                11

                                                                              =
                               5
                                                                                15
                             =
                                                            [2]
                        Penerbitan Pelangi Sdn Bhd. All Rights Reserved.                                     [3]
                                                                           4
                                                                                    2
                                                                                3
                               64
                             (  1  1 )                                 (c)   6   ×   5   ×   4
                         (ii)  8   ×   8   × 12                            =  1                              [2]
                             =  3                           [2]              5
                               16                                             130   13
                  12  (a)                                          14  (a)  (i)   180   =  18                [1]
                                  Box A                  Box B                 35    7
                                                   3                      (ii)  180   =  36                  [1]
                                                   10     Red          (b)   35   ×   34
                                                                           130   129
                                                                           =  119                            [2]
                                                   7      Black             1677
                                 3       Red       10                  (c)  (i)   45   ×   44   =   99       [2]
                                 14  5             2                          140   139   973
                                                                               95
                                                                                           45
                                                                                     45
                                                                                                 95
                                     14  Black     10     Red             (ii)  140   ×   139  +   140   ×   139
                                                                                855
                                 6                                            =  1946                        [3]
                                 14     White      8      Black         7    6    6    7     2
                                                   10              15     ×  x – 1  +   x   ×  x – 1  =   5
                                                                        x
                                                                            42       42      2
                                                   2                      x(x – 1)   +   x(x – 1)   =   5
                                                   10     Red                        84      2
                                                                                           =
                                                                                   x(x – 1)  5
                                                          Black                  2
                                                        7                       x  – x – 210 = 0
                                                   1    10             x = 15 or x = −14 (invalid)           [4]
                                                   10
                                                          White
                                                            [5]
                        Cambridge IGCSE
                                         TM
                  180     Ace Your Mathematics






         Answers.indd   180                                                                                      15/03/2022   11:08 AM
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