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答案





                                                                        Based on the table, the competition among the


                       模拟试卷 1   / Model Paper 1                        seedlings in container Z is the highest, followed
                                                                       by X and Y. Therefore, the seedlings in container Z
                                                                       are the shortest, followed by X and Y.
                   试卷一 / Paper 1

                                                                  6.  B  根朝着地心引力向下生长,而嫩芽向上生
                          双语特优A+系列科学, 版权所有·侵权必究
                  1.  D  穿山甲与鳄鱼一样有坚硬的鳞片,河豚与                            长。
                       豪猪一样身上有尖刺,而蜈蚣与蝎子一样                               The roots grow downwards towards gravity while
                       有毒刺。                                            the shoots grow upwards.
                        The pangolin has hard scale-like skin which is
                                                  has
                       similar to the crocodile. The �����sharp     7.  A  T  是杂食动物,因为它吃植物(P)和其
                       quills (needles) on its body which is similar to the
                       porcupine. The centipede has a poisonous sting   他动物(R 和 U)。鸡是杂食动物。
                       which is similar to the scorpion.                T is an omnivore because it eats plants (P) and other
                                                                       animals (R and U). The chicken is an omnivore.
                  2.  B  盆  Y  里的幼苗会更健康地生长,因为对
                       水、矿物质和空间的竞争较少。                             8.  D  在油棕园里大规模饲养牛不是保护和复育
                        The seedlings in pot Y will grow healthier because   生物的活动。
                       there is less competition for water, minerals and           Rearing  cows  on  a  large  scale  in  oil  palm
                       space.                                          plantations is not a preservation and conservation
                                                                       activity of living things.
                  3.  D  饲养猫头鹰会减少老鼠的数量,同时增加
                       油棕的产量。与猫头鹰竞争食物(老鼠)                         9.  A
                       将减少眼镜蛇的食物来源。D 与饲养猫头
                       鹰无关。                                      10.  C  根据资料,Q 的脚掌最长,其次是 R、P
                        Rearing  of  owls  would  reduce  the  number  of   和 S。
                       rats and at the same time increase the oil palm           Based on the information, the foot of Q is the longest
                       production. Competition between the owls and the   and is followed by R, P and S.
                       snakes for food (rats) would reduce the food supply
                       of cobras. D is not related to the rearing of owls.
                                                                 11.  B  单摆的摆动和滴水一样是有规律的,可用
                                                                       于测量时间。
                  4.  A  海葵与寄居蟹之间的相互关系被称为互利
                       共生。这个关系对双方有利,寄居蟹获得                               The pendulum swing is uniform, like the water
                                                                       dripping and can be used to measure time.
                       海葵的保护,而海葵在寄居蟹移动时获得
                       免费交通。                                     12.  D  物体 J 的速度为 30 厘米/秒,K 的速度为
                        The interaction between the sea anemone and the   50 厘米/秒,L 为 25 厘米/秒。根据物体
                       hermit crab is known as mutualism. This interaction
                       is  beneficial  to  both  parties  whereby  the  sea   的速度,从慢到快的排列是 L、J、K。
                       anemone gives protection to the hermit crab while           The speed of object J is 30 cm/s, K is 50 cm/s and L is
                       the sea anemone gets free transportation when the   25 cm/s. The speed of the objects according to their
                       hermit crab moves.                              increasing order is L, J, K.


                  5.  D  根据表格,容器 Z 里的幼苗之间的竞争是                    13.  B  平静的水面就像镜子一样能够反射光。
                       最大的,其次是 X 和 Y。因此,容器 Z 里                          A calm water surface is like a mirror that is able to
                       的幼苗最矮,其次是 X 和 Y。                                r������


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