Page 21 - The Effect of Hydrogen and Hydrides - ebook first test
P. 21

2                                 ̅ 3
                              ∗
                            ∆   =                                    
                                  3  [   (−∆   ′ℎ      − Δ   ℎ      (      ) −    Δ   ℎ      (          ) − ∆   ℎ      +    ∆       )] 2
                                                                                           
                                                                ∗
                                      ∗
                                              ℎ                                                      
                                                                ̅   

                                                                   ∗
                                                          ̅ =    + 2        
                                                           
                                                               



                                                                  ̅
                                ∗
                                  =                                
                                                   ℎ    
                                                                                  ℎ    
                                                                                          
                                    ∗
                                                               ∗
                                      (−∆   ′          − Δ                (      ) −    Δ   ℎ      (          ) − ∆           +    ∆       )
                                                                                                 
                                                                                          
                                            ℎ    
                                                                              
                             ∗
                              ⁄
                                ∗
                         ∗
                                     ⁄
                           =       =         
                                      
                                                                                                  ∆   ′ℎ    
                                                                                                      ℎ    
                                                                          ,     (  )
                                                   ′        
                                                ∆     ℎ      =  V ̅                    (             )
                                                                   
                                                            −    
                                                                          
                                  
                                              =
                                                                            
                                                                                
                                              =
                                              =

                              ̅   −    
                              V               =
                                     ,     ()  =                      

                                                                                                    

                                  
                                              =                                      
                                                                                       =    /     ℎ         
                                                                                       
                                                                                            
                                                    ℎ  


                   ⁄
                        ≪ 1


                                                                             1
                                                                                   2
                                                        2
                                         ∆   ℎ      =  1 −     ∆ + 1 −    2     [Δ ∙    + 4(1 +   )     ]
                                                       
                                              =




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