2
2
3
= ∫ [ ( ( ( ))) + ∑ (∇ ( )) + (∇ ) ] + +
=1 2 2
=
=
=
2
3
2
= ∫ [ ( , ) − ( ) + ∑ 2 (∇ ( )) + 2 (∇ ) ]
=1
( , ( )) − ( , = 0)
( ) = ( , ( )) + − ( − )
= =
,
= =
,
=
, ,
Copyright © Advanced Nuclear Technology International Europe AB, ANT International, 2019.