2 ̅̅̅̅̅̅̅
̅ = ∑ ( ) ( ) +
=1
−
2
3
∗
,
= ∑ ∑ ( ) ( )⌈ 2 ̅̅̅̅̅̅̅ 2̅̅̅̅̅̅̅ 2 ̅̅̅̅̅̅̅ 2̅̅̅̅̅̅̅ 1 (2 ) 3 ( ){ 2 ( )} { 2 ( )}
( )⌉ − ∑ ∑ ∫
( )
( )
( ) −
2
2
=1 =1 =1 =1
( ) ( )
− − ∑ 2 ̅̅̅̅̅̅̅
2
=1
α
,
, ( )
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