Page 351 - The Effect of Hydrogen and Hydrides - ebook first test
P. 351

     
                                                                                  
                                                                                               ∆  
                                                                             2
                                                                        ⁄
                                                                        ℎ  = 4 3       

                                         4
                                        =        (∆   ℎ      + ∆   ℎ      + ∆   ℎ     ) + 2        + 4        
                                             2
                                                                             2
                                         3          ℎ                                    
                                ℎ    
                             ∆     ℎ          =

                                                                                     



                              ∆   ℎ           =
                                           

                              ∆   ℎ           =
                                      



                                              =

                                              =


                                                                    ∆   ℎ                    
                                                                         ℎ    








                                              ℎ    
                                 ∆  ̅ ℎ      ∆  ̅       
                                               
                                                                                             
                                                             ̅   −    
                                                               
                                                                                   ̅   −    
                                                               ∆  ̅ ℎ      ∆  ̅ ℎ             
                                                                             
                                                                                   
                                                                   

                                                            




                                                                    
                                                      ℎ    
                                                    ∆                 =     ̅          ∆  ̅ ℎ    
                                                                 −    
                                                                                 

                                                                ∆  ̅ ℎ    
                                                        ∆   ℎ      =     ̅            
                                                                   −    
                                                                
                                                                       ℎ    
                                                                     ∆  ̅       
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