+ = 1 − [H]
+ =
1 − [H]
= 1−[H]
)
1−[H] + (1 − 1−[H]
′(1 − [H] )
=
′(1 − [H] ) + (1 − [H] )
′
=
(1 − )
(1 − [H] )[H] = { (1 − [H] ) + (1 − [H] )}[H] − ′(1 − [H] )[H]
′
′([H] − [H] ) + (1 − [H] )[H]
[ ] = (1 − [H] ) + ′([H] − [H] )
+ [H]
[H] = 1 +
′([H] − [H] )
=
δ
(1 − [H] )
at