Page 366 - The Effect of Hydrogen and Hydrides - ebook first test
P. 366

     
                                                                       
                                                              
                                                            +    =  1 − [H]   
                                                           
                                                              
                                                                          


                                                                       
                                                              
                                                            +    =      
                                                           
                                                              
                                                                1 − [H]        
                                                                                  
                                                                                                

                                                               
                                                                                   
                                                                    
                                                 
                                                 =               1−[H]         
                                                  
                                                                            )         
                                                             1−[H]          +    (1 −        1−[H]   
                                                                     
                                                        
                                                                                  
                                                             ′(1 − [H] )
                                                                      
                                                    
                                                        =               
                                                                            
                                                       ′(1 − [H] ) + (1 − [H] )
                                                                
                                                                  
                                                                              
                                                                
                                                                   
                                                                        
                                                       ′
                                                         =                
                                                                (1 −    )
                                                                
                                                             
                                                                       
                                                                    
                                                                       
                                                                       
                              (1 − [H] )[H]     = {   (1 − [H] ) + (1 − [H] )}[H]         −   ′(1 − [H] )[H]        
                                                 ′
                                                                                          
                                                           
                                       
                                                                         
                                         
                                               
                                                                               
                                                                                            
                                                             
                                                                 
                                                    ′([H]         − [H] ) + (1 − [H] )[H]       
                                                                             
                                                                               
                                                                   
                                                           
                                           [  ]     =  (1 − [H] ) +   ′([H]        − [H] )     
                                                  
                                                              
                                                                               
                                                                                 
                                                                
                                                                          
                                                                 + [H]       
                                                       [H]     =  1 +        
                                                              
                                                           ′([H]         − [H] )
                                                                       
                                                        =                
                                                                   δ
                                                            (1 − [H] )
                                                                   at
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