Page 111 - SK Year 5 Mathematics DLP
P. 111
8 (RM254 892.75 – RM86 301.90) ÷ 5 =
14 RM 3 3 7 1 8. 1 7
1 4 14 1 17 5
RM 2 5 4 8 9 2 . 7 5 5 RM 1 6 8 5 9 0.8 5
− RM 8 6 3 0 1 . 9 0 − 1 5
1 8
RM 1 6 8 5 9 0 . 8 5 − 1 5
3 5
− 3 5
0 9
− 5
4 0
− 4 0
0 8
− 5
3 5
− 3 5
0
(RM254 892.75 – RM86 301.90) ÷ 5 = RM33 718.17
1 Solve these.
a RM1 502 + 7 × RM2 865 =
b 5 × RM4 857 − RM2 142.80 =
c RM45 193.05 + RM28 837.25 × 12 =
d RM653 008 − RM25 842.70 × 16 =
e RM284 703.80 + RM43 879 ÷ 25 =
f RM109 275.60 − RM32 760 ÷ 18 =
2 Calculate.
a (RM3 484.65 + RM4 092.80) × 9 =
b (RM192 558.80 ÷ 28) – RM5 854.75 =
c RM118 549.45 – (26 × RM4 091.90) =
d RM767 041.88 + (RM505 050 ÷ 100) =
103
3.2.1 • Encourage pupils to check the answers using calculators.
