Page 111 - SK Tahun 5 Matematik
P. 111
8 (RM254 892.75 – RM86 301.90) ÷ 5 =
14 RM 3 3 71 8. 17
1 4 14 1 17 5
RM 254 892 . 75 5 RM 1 685 9 0.85
− RM 86 30 1 . 90 − 15
18
RM 1 6 8 590 . 85 − 15
35
− 35
09
− 5
40
− 40
08
− 5
35
− 35
0
(RM254 892.75 – RM86 301.90) ÷ 5 = RM33 718.17
1 Selesaikan.
a RM1 502 + 7 × RM2 865 =
b 5 × RM4 857 − RM2 142.80 =
c RM45 193.05 + RM28 837.25 × 12 =
d RM653 008 − RM25 842.70 × 16 =
e RM284 703.80 + RM43 879 ÷ 25 =
f RM109 275.60 − RM32 760 ÷ 18 =
2 Hitung.
a (RM3 484.65 + RM4 092.80) × 9 =
b (RM192 558.80 ÷ 28) – RM5 854.75 =
c RM118 549.45 – (26 × RM4 091.90) =
d RM767 041.88 + (RM505 050 ÷ 100) =
• Minta murid menyemak jawapan dengan menggunakan 103
3.2.1
kalkulator.

