Page 56 - SP015 Past Years PSPM Chapter 1 -5 Ver.2020
P. 56

PHYSICS PSPM SEM 1  1999 - 2017


               27.   (a)  Total distance travelled from the graph,   s = 1875 m
                                               -2
                                   -2
                                                             -2
                     (b)  a 1  = 3.33 m s ,    a 2  = 0 m s ,    a 3  = –5.0 m s
               28.   (a)  Yes, because there is change of direction.   (b)  Yes, the car is able to stop before it hits the tree.
               29.   s = 67 m
                             -1
               30.   v = 70 m s
               31.   t = 4.17 s
                               -2
               32.   a = 4.03 m s
                                -1
               33.   v = 42.54 m s
                                  -1
               34.   (a)  v = 19.7 m s      (b)  t = 4.63 s

               35.   Free falling body is vertical motion of a body under gravitational force only. (without air resistance or
                     any external force). Or Free falling body is a vertical motion at constant acceleration g.

               37.   (a)  t = 2 s
                     (b)  (i)  The advertisement board will hit the car.   (ii)  The advertisement board will not hit the car.
               38.   (a)  H = 11.47 m       (b)  t H  = 1.53 s
                                                                                -1
               39.   (a)  Maximum distance from ground = 42.87 m   (b)  v = 31.78 m s
               40.   t = 1.53 s
               41.   t = 0.6 s
                                                            -1
               42.   (a)  s = 17.52 m       (b)  v = 19.49 m s    (c)  t = 2.45 s
               43.   (a)  No, the acceleration of the ball is not zero at the  maximum height because there  is  acceration is
                                                  -2
                        always constant @ g = 9.81 m s .

                                   -1
               44.   (a)  v = 24.77 m s     (b)  t = 2.02 s
               45.   t = 119.63 s
                                   -1
               46.   (a)  u = 19.62 m s     (b)  H = 19.62 m
                                   -1
               47.   (a)  u = 44.29 m s     (b)  t = 4.51 s
                                         -1
               48.   s x  = 20 m,   v = 39.56 m s   at  82.8 below the horizontal,   t = 4 s
               49.   (a)  t = 20.2 s        (b)  s x  = 3030 m
               50.   (a)  t = 0.47 s        (b)  s x  = 0.94 m
                                  -1
               51.   (a)  v = 1.96 m s      (b)  h = 1.23 m
                               -1
               52.   u x  = 3.03 m s
               53.   (a)  t = 0.55 s        (b)  s x  = 1.38 m
               54.   R = 17.5 m
                                                          -1
               55.   (a)  t = 0.0622 s      (b)  u x  = 482 m s
                                   -1
               56.   (b)  v = 51.76 m s     (d)  t = 3.78 s       (e)  R = 151.2 m
                          2
                         u sin 2  
               57.   H 
                            2 g
               58.   (a)  h = 11.43 m    (b)  Direction of the arrow is upward.   (c)  U = 11.2 J
                                   -1
                                                       -1
               59.   (a)  u = 19.95 m s    (b)  v = 18.78 m s     (c)  h = 2.32 m
               60.   R = 510 m

                                  -1
               61.   (a)  u = 10.8 m s    (b)  h = 1.06 m     (c)  Increase the initial take-off speed and jump angle = 45.
               62.   (a)  t = 3.92 s     (b)  Distance = 24.98 m   (c)  v = 29.83 m s -1

               63.   (a)  The  displacement  and  velocity  in  a  projectile  motion  can  be  analysed  separately  in  the  x-  and  y-
                        directions because both displacement and velocity are vector quantities, so they can be resolved into
                        x- and y-directions.
                     (b)  t = 2.65 s

                               -1
               64.   v = 42.7 m s ,     = 16.7 below horizontal
               65.   (a)  t = 9.21 s     (b)  x = 638 m
               66.   (a)  t = 1.53 s     (b)  s = 20.68 m

               67.   Free fall motion is a motion when the body is not exerted by any force except by the gravitational force.
                     Projectile motion is a motion that involves the resultant of two motion which is the vertical motion (free
                     fall) and the horizontal motion (linear motion).

                                                                                   -1
               68.   (a)  Both motions are under the influence of gravity.   (b)  u = 8.66 m s


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