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ST	EW      iaþ.






                                                                                           ELEMENTS BOOK 11



            ποιήσει ἐν τῷ ὑποκειμένῳ ἐπιπέδῳ εὐθεῖαν. ποιείτω τὴν And let the plane through AB and BC have been pro-
            ΒΖ. ἐν ἑνὶ ἄρα εἰσὶν ἐπιπέδῳ τῷ διηγμένῳ διὰ τῶν ΑΒ, duced. So it will make a straight-line as a common sec-
            ΒΓ αἱ τρεῖς εὐθεῖαι αἱ ΑΒ, ΒΓ, ΒΖ. καὶ ἐπεὶ ἡ ΑΒ ὀρθή  tion with the reference plane [Def. 11.3]. Let it make
            ἐστι πρὸς ἑκατέραν τῶν ΒΔ, ΒΕ, καὶ τῷ διὰ τῶν ΒΔ, BF. Thus, the three straight-lines AB, BC, and BF
            ΒΕ ἄρα ἐπιπέδῳ ὀρθή ἐστιν ἡ ΑΒ. τὸ δὲ διὰ τῶν ΒΔ, ΒΕ are in one plane—(namely), that drawn through AB and
            ἐπίπεδον τὸ ὑποκείμενόν ἐστιν· ἡ ΑΒ ἄρα ὀρθή ἐστι πρὸς τὸ  BC. And since AB is at right-angles to each of BD and
            ὑποκείμενον ἐπίπεδον. ὥστε καὶ πρὸς πάσας τὰς ἁπτομένας BE, AB is thus also at right-angles to the plane (passing)
            αὐτῆς εὐθείας καὶ οὔσας ἐν τῷ ὑποκειμένῳ ἐπιπέδῳ ὀρθὰς  through BD and BE [Prop. 11.4]. And the plane (pass-
            ποιήσει γωνίας ἡ ΑΒ. ἅπτεται δὲ αὐτῆς ἡ ΒΖ οὖσα ἐν τῷ ing) through BD and BE is the reference plane. Thus,
            ὑποκειμένῳ ἐπιπέδῳ· ἡ ἄρα ὑπὸ ΑΒΖ γωνία ὀρθή ἐστιν. AB is at right-angles to the reference plane. Hence, AB
            ὑπόκειται δὲ καὶ ἡ ὑπὸ ΑΒΓ ὀρθή· ἴση ἄρα ἡ ὑπὸ ΑΒΖ γωνία  will also make right-angles with all straight-lines joined
            τῇ ὑπὸ ΑΒΓ. καί εἰσιν ἐν ἑνὶ ἐπιπέδῳ· ὅπερ ἐστὶν ἀδύνατον. to it which are also in the reference plane [Def. 11.3].
            οὐκ ἄρα ἡ ΒΓ εὐθεῖα ἐν μετεωροτέρῳ ἐστὶν ἐπιπέδῳ· αἱ τρεῖς And BF, which is in the reference plane, is joined to it.
            ἄρα εὐθεῖαι αἱ ΒΓ, ΒΔ, ΒΕ ἐν ἑνί εἰσιν ἐπιπέδῳ.     Thus, the angle ABF is a right-angle. And ABC was also
               ᾿Εὰν ἄρα εὐθεῖα τρισὶν εὐθείαις ἁπτομέναις ἀλλήλων ἐπὶ assumed to be a right-angle. Thus, angle ABF (is) equal
                                    þ                          one plane.
            τῆς ἁφῆς πρὸς ὀρθὰς ἐπισταθῇ, αἱ τρεῖς εὐθεῖαι ἐν ἑνί εἰσιν to ABC. And they are in one plane. The very thing is
            ἐπιπέδῳ· ὅπερ ἔδει δεῖξαι.                          impossible. Thus, BC is not in a more elevated plane.
                                                                Thus, the three straight-lines BC, BD, and BE are in

                                                                   Thus, if a straight-line is set up at right-angles to three
                                                                straight-lines cutting one another, at the (common) point
                                                                of section, then the three straight-lines are in one plane.
                                                                (Which is) the very thing it was required to show.

                               G
                                                                                  Proposition 6
                                             A
                                      .
               ᾿Εὰν δύο εὐθεῖαι τῷ αὐτῷ ἐπιπέδῳ πρὸς ὀρθὰς ὦσιν,   If two straight-lines are at right-angles to the same
            παράλληλοι ἔσονται αἱ εὐθεῖαι.                      plane then the straight-lines will be parallel. †
                                                                                   C
                                                                                                 A

                               D     E        B                                   D              B








                                                                                        E



               Δύο γὰρ εὐθεῖαι αἱ ΑΒ, ΓΔ τῷ ὑποκειμένῳ ἐπιπέδῳ     For let the two straight-lines AB and CD be at right-
            πρὸς ὀρθὰς ἔστωσαν· λέγω, ὅτι παράλληλός ἐστιν ἡ ΑΒ τῇ  angles to a reference plane. I say that AB is parallel to
            ΓΔ.                                                 CD.
               Συμβαλλέτωσαν γὰρ τῷ ὑποκειμένῳ ἐπιπέδῳ κατὰ τὰ Β,  For let them meet the reference plane at points B and
            Δ σημεῖα, καὶ ἐπεζεύχθω ἡ ΒΔ εὐθεῖα, καὶ ἤχθω τῇ ΒΔ D (respectively). And let the straight-line BD have been
            πρὸς ὀρθὰς ἐν τῷ ὑποκειμένῳ ἐπιπέδῳ ἡ ΔΕ, καὶ κείσθω joined. And let DE have been drawn at right-angles to
            τῇ ΑΒ ἴση ἡ ΔΕ, καὶ ἐπεζεύχθωσαν αἱ ΒΕ, ΑΕ, ΑΔ.     BD in the reference plane. And let DE be made equal to
               Καὶ ἐπεὶ ἡ ΑΒ ὀρθή ἐστι πρὸς τὸ ὑποκείμενον ἐπίπεδον, AB. And let BE, AE, and AD have been joined.
            καὶ πρὸς πάσας [ἄρα] τὰς ἁπτομένας αὐτῆς εὐθείας καὶ   And since AB is at right-angles to the reference plane,
            οὔσας ἐν τῷ ὑποκειμένῳ ἐπιπέδῳ ὀρθὰς ποιήσει γωνίας. it will [thus] also make right-angles with all straight-lines
            ἅπτεται δὲ τῆς ΑΒ ἑκατέρα τῶν ΒΔ, ΒΕ οὖσα ἐν τῷ ὑπο- joined to it which are in the reference plane [Def. 11.3].

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