Page 16 - Trigonometry
P. 16
Example 5:
Evaluate the following,
1 2
3 3
sin [cos −1 ( )] cos [tan −1 ( )]
4 5
3 4
5 6.482
tan [sin −1 (− )] sin [tan −1 ( )]
6 3
√11.48
1 The long way of performing calculations like this is
to let
3 3
= cos −1 ( ) or = cos( )
4 4
As you can see in the diagram
on the left,
4
√4 −3 2 √7
sin( ) = =
4 4
Therefore,
√7
= sin −1 ( )
4
For problem 1,
12
