Page 47 - More Higher algebra

Confirm the result by replacing x by 11 in the original

expression,
1 6−11
( ) − 32 = 0
2

2. Find the value of x in the expression,

2
1 −1

√16 = ( )
2

This is the same as,

2
1 −1
16 2 = ( )
2

2
1 −1
ln (16 2) = ln [( ) ]
2

1
2
ln(16) = ( − 1)ln [ ]
2 2

2
ln(0.5) ( − 1)
2
= ( − 1) = −
2 ln(16) 4

2
2 = −( − 1)
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