Page 52 - Fizik Tingkatan 4 KSSM
P. 52
Penyelesaian:
Jadual 2.5
Halaju, v / m s –1
20 Masa Sesaran Pecutan
18
0 – 10 s Sesaran Pecutan
16
= luas A = kecerunan graf
14 –2
= 10 × 10 = 0 m s
12 = 100 m
10
8 10 – 30 s Sesaran Pecutan
= luas B 16 – 10
6
A B C =
1
4 = (10 + 16)(20) 30 – 10
2 = 0.3 m s –2
2
= 260 m
0 Masa, t / s
5 10 15 20 25 30 35 40 45 50
30 – 50 s Sesaran Pecutan
Rajah 2.32 = luas C 0 – 16
=
1 50 – 30
Sesaran selepas 30 s = 100 + 260 = × 20 × 16 = –0.8 m s –2
2
= 360 m = 160 m
Sesaran selepas 50 s = 100 + 260 + 160
= 520 m
(a) Graf sesaran-masa (b) Graf pecutan-masa
–2
Pecutan, a / m s
Sesaran, s / m
0.3
0.2
520
500 0.1
0 Masa, t / s
10 20 30 40 50
400 –0.1
360 –0.2
300 –0.3
–0.4
200 –0.5
–0.6
100 –0.7
–0.8
0 Masa, t / s –0.9
10 20 30 40 50
Rajah 2.33 Rajah 2.34
44 2.2.5
