Page 21 - Modul A+1 Kimia Tingkatan 4
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(b) & (c) 2. (a) Kaedah II/ Method II
(b) Hidrogen lebih reaktif daripada logam Q dan boleh
Suhu (°C)
Temperature (°C) menurunkan oksida logam Q.
Hydrogen is more reactive than metal Q and can reduce
the oxide of metal Q.
90
(c) Untuk menyingkirkan lapisan oksida pada bahan.
To remove the oxide layer on the substance.
(d) Untuk membenarkan oksigen masuk ke dalam mangkuk
85 pijar supaya berlaku pembakaran lengkap.
To allow oxygen to enters the crucible for complete
combustion to occur.
(e) (i) Tidak / No
Takat lebur 80
Melting point (ii) Plumbum tidak mudah terbakar dengan oksigen.
Cannot react readily with oxygen .
(f) (i) Untuk melihat gelembung gas yang terhasil. Jika
©PAN ASIA PUBLICATIONS
75 gelembung gas terhasil, gas hidrogen sedang
mengalir.
To see the gas bubbles produced. If gas bubbles are
produced, the hydrogen gas is flowing.
70 Masa (s)
0 30 60 90 120 150 180 210 Time (s) (ii) Etanol ialah bahan api bersih yang terbakar tanpa
menghasilkan jelaga.
(d) Haba yang diserap digunakan untuk mengatasi daya Ethanol is a clean fuel that burns without producing
tarikan antara zarah. soot.
Heat absorbed is used to overcome the forces of attraction (iii)
between particles. Kuprum Oksigen
(e) Suhu malar yang diperoleh apabila bahan W dipanaskan Copper Oxygen
dalam kukus air dan berubah daripada pepejal kepada
cecair. Jisim, (g) 6.4228 1.6057
Constant temperature obtained when substance W is Mass, (g)
heated in water bath and changes from solid to liquid. Bilangan mol 6.4228 1.6057
Number of moles 64 = 0.1004 mol 16 = 0.1004
BAB 3 Nisbah mol atom 0.1004 0.1004
Soalan Berformat SPM Ratio of moles of 0.1004 = 1 0.1004 = 1
atoms
Kertas 1/ Paper 1 Formula empirik/ Empirical formula: CuO
1. A 2. D 3. A 4. A 5. D
6. A 7. C 8. B 9. B 10. B
Bahagian B/ Section B
Kertas 2/ Paper 2 3. (a) (i) Berdasarkan skala karbon-12, jisim atom relatif
suatu unsur adalah jisim purata satu atom unsur jika
Bahagian A/ Section A
120 dibandingkan dengan jisim satu atom karbon-12.
1. (a) Bil mol/ Number of moles = 24 = 5 mol Based on the carbon-12 scale, the relative atomic
(b) (i) Bilangan mol/ Number of moles = 180 mass of an element is the average mass of one atom
2(1) + 16 of the element when compared with of the mass of
= 10 mol one carbon-12 atom.
Bilangan molekul/ Number of molecules (ii) 1 atom X × JAR/ RAM atom X
= 10 × 6.02 × 10 = 6.02 × 10 24 = 4(2 atom × JAR/RAM atom karbon/carbon atom)
23
(ii) 10 mol air dengan jisim 180 g mempunyai 6.02 × 1 × JAR/ RAM atom X = 4(2 × 12)
10 molekul air. JAR/ RAM atom X = 96
24
10 mol of water with the mass of 180 g has 6.02 × (b) (i)
24
10 water molecules. Unsur Karbon Hidrogen
(c) (i) CH + 2O → CO + 2H O Element Carbon Hydrogen
2
2
4
2
(ii) Kualitatif/ Qualitative:
Bahan tindak balas ialah metana dan oksigen, hasil Jisim (g) / Mass (g) 82.75 17.25
tindak balas ialah karbon dioksida dan air. Bilangan mol 82.75 = 6.9 17.25 = 17.25
Reactants are methane and oxygen, products are Number of moles 12 1
carbon dioxide and water. Nisbah mol 6.9 17.25
Kuantitatif/ Quantitative: Ratio of moles 6.9 = 1 6.9 = 2.5
1 mol metana bertindak balas dengan 2 mol oksigen
untuk menghasilkan 1 mol karbon dioksida dan 2 Nisbah mol paling
mol air. ringkas 2 5
1 mol of methane reacts with 2 mol of oxygen to Simplest ratio of moles
form 1 mol of carbon dioxide and 2 mol of water. Formula empirik/ Empirical formula: C H
120 2 5
(d) Bilangan mol/ Number of moles = 24000 = 0.005 mol CO 2 (C H ) = 58
5 n
2
1 mol CH menghasilkan 1 mol CO 2 n[2(12) + 5(1)] = 58
n = 2
4
1 mol of CH produces 1 mol of CO 2 Formula molekul/ Molecular formula = (C H )
4
2
0.005 mol CH menghasilkan 0.005 mol CO 2 = C H 5 2
4
0.005 mol of CH produces 0.005 mol of CO 2 4 10
4
JAWAPAN MG-14
Jisim/ Mass = 0.005 × [12 + 4(1)] = 0.08 g
