Page 17 - 1202 Question Bank Physics Form 4
P. 17

4.  (a)  m = r V, l = ! V                           (d)  Graph of T   against l
                                                                              2
                             3
                  (b)  •  No measuring instrument can measure density and volume   T  / s 2
                                                                      2
                       accurately.
                     •  No suitable object for standard density and standard volume.
                     •  Units for derived quantity become very complex.  2.8
                     •  Hinder effective communication among physicists.
                                                                     2.4
                5.  (a)  Draw graph of V against x. Extrapolate it to find V  when
                                                        0
                     x = 0. V  is 46 L.
                          0
                  (b)  Using interpolation method V is 41 L when x = 50 km, hence   2.0
                     the petrol consumption is
                     V – V  = 46 – 41                                1.6
                         0
                         = 5 L
                        40.0 ©PAN ASIA PUBLICATIONS
                  (c)                                                1.2
               Distance,   40  60  80  100  120  140  160  180  200
               x / km                                                0.8
               Volume                                                0.4
               of petrol,  42.60 40.05 37.93 35.80 33.25 31.55 30.28 27.30 25.60
               V / L
                                                                     0
                                                                          10   20  30  40  50  60  70   80 I / cm
                  (d)  Graph of remaining volume of petrol, V against distance, x  2.38 – 0
                                                                    (e)  Gradient, s =
                                                                                 60 – 0
                                                                               = 0.0397 s  cm –1
                                                                                     2
                    Remaining volume of petrol, V / L                           4π 2
                                                                             g =
                                                                                 s
            Chapter 1 – Chapter 2
                                                                               = 994 cm s –2
                   50
                   40
                                                                CHAPTER 2
                   30
                   20
                                                                                     Paper 1
                   10
                                                                  1.  D  Distance is the total length travelled by the security personnel
                                                        x / km
                    0                                                 = 5 + 7 + 5 + 10 + 10 + 10 + 10
                        20  40 60  80 100 120 140 160 180 200
                                                                      = 57 m.
                                                                      Displacement is the distance travelled in a specified direction PQ
                                                                      = 7 + 10 +10
                                  Paper 3                             = 27 m.
                1.  (a)  Measure l  and l  and then taking average.    2.  A   Not sufficient information to check whether the object moves
                           1   2
                                                                      with constant velocity or not (the dots do not display consistent
                                      Clamp                           equal spacing pattern).
                                                                  3.  A  u =  0.2 cm
                                                                         0.02 s
                                                                         = 10 cm s –1
                                          l +  l
                              l  l  l   l  =  1  2                    v =  1.4 cm
                                1   2
                                           2                             0.04 s
                                                                         = 35 cm s –1
                                                                      ∆ t = 4.5 × 0.02
                                                                         = 0.09 s (From 1  the mid-point to the end mid-point)
                                                                                   st
                                                                      Acceleration =   35 – 10
                                                                                 0.09 s
                              Centre of bob                                    = 278 cm s –2
                  (b)
                                                                  4.  D  10 ticks = 0.2 s
                        l / cm    t / s     T / s    T / s 2             4 cm
                                                      2
                                                                      u =   0.2 s
                        20.0      17.65    0.833     0.780               = 20 cm s –1
                        30.0      22.15    1.108     1.228            v =  24 cm
                                                                         0.2 s
                                  25.00    1.250     1.563               = 120 cm s
                                                                              –1
                        50.0      27.95    1.398     1.954            ∆ t  = (6 – 1) × 0.2 s
                                                                         = 1 s
                        60.0      30.80    1.540     2.372                      (120 – 20) cm s –1
                                                                      Acceleration =   1 s
                  (c)  (i)  The manipulated variable: length of pendulum, l     = 100 cm s –2
                     (ii)  The responding variable: the period T of the pendulum

              108




         Answer QBank Physics F4.indd   108                                                                   10/02/2022   4:03 PM
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