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Angles in parallelograms and trapeziums
                                     Look at parallelogram ABCD below. Cut out Z.ABC along the dotted line EF, and
                                     place it next to ^FCD.












                                                                                                     C,B
                                     We see they form a straight llne.The sum of the two angles is 180°. ^ABC ar\d
                                     ABCD are a pair of interior angles of the parallelogram. They are between the
                                     parallel lines, AB and DC. Another pair of interior angles which are between the
                                     parallel lines, >16 and DC, are ^>1DCand aDAB.
                                     Look at trapezium PQRS. AQRS is cut off along the dotted line TU, and placed next
                                     to APQU.

                                                                                Q




                                         Q                                       □


                                     The sum of the two angles is also  180°.
       The sum of a pair of
       interior angles in a          APQR and  AQRS are a  pair of interior angles of the trapezium. They are between
       quadrilateral is 180°.        the parallel lines,  PQ and SR. The other pair of interior angles, AQPS and APSR,
                                     also add up to 180°.
       The sum of all interior
       angles in a quadrilateral     Look the square and the rectangle in Example 2. The sum of each pair of interior
       = 180° X 2 = 360°.            angles is  180°.


                                      Example 3


                                     0 AeCD is a parallelogram ./D/46= 124°.

                                         Find                                              124°
                                         a)   zlx,         b)  ABCD.

      A BAD
                                         Solution
              another
                                         a)  Zx+124° =  180°     Interior angles between the parallel lines/4D and 6C.
                                                   ^x= 180°- 124°
                                                      =  56°
                                         b)   56° +  ABCD = 180°  Interior angles between the parallel lines 46and DC.
                                                   ^6CD= 180°-56°
                                                         =  124°




                        Angles and Their Properties
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