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SPM Chemistry A xplosive Module (Chemistry A Ticket For “U”) ANSWERS

34 Carbon Compound C Compound T is propanol (alcohol). Compound U is
propanoic acid (carboxylic acid). Compound U reacts
with magnesium to form salt and hydrogen gas.

Sebatian T adalah propanol (alcohol). Sebatian U
adalah asid propanoik (asid karboksilik). Sebatian U
bertindak balas dengan magnesium untuk membentuk
garam dan gas hidrogen.

-1
3
3
35 Carbon Compound D No of mole C 3H 8 = 48 cm / 24dm mol
= 2 mol
1 mol C 3H 8  3 mol CO 2
2 mol C 3H 8  6 mol CO 2
3
Volume of CO 2= 6 mol x 24dm mol -1
3
= 144 dm

36 Carbon Compound A Empirical formula of lactic acid = CH 2O
Formula empiric asid laktik
Molecular formula of lactic acid = 3 (CH 2O)
Formula molekul asid laktik
= C 3H 6O 3

37 Carbon Compound B A fruit is an ester which has the general formula
R mCOOR n. An ester is formed through esterification
between an alcohol and carboxylic acid.

Buah-buahan merupakan ester dengan formula am
R mCOOR n. Ester terhasil melalui proses pengesteran
di antara alcohol dan asid karboksilik.

38 Oxidation and Reduction D To prevent rusting, iron should be in contact with
more electropositive metal. Magnesium is more
electropositive than iron because its position in the
electrochemical series is higher than that of iron.

Bagi mengelakkan pengaratan, ferum hendaklah
bersentuhan dengan logam yang lebih elektropositif.
Magnesium lebih elektropositif daripada ferum
kerana kedudukannya lebih tinggi berbanding ferum
di dalam siri elektrokimia.

39 Oxidation and Reduction C KClO 3
(+1)+ Cl + (-6) = 0
Cl -5 = 0
Cl = +5
KCl
(+1) + Cl = 0
Cl = -1

+5  -1

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