Page 111 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

103
2.

×
×
R R 75 43.532 10 3 R R
g GG
Ω
Ω
* % R = = = 74.871 , R = D L = 947.368 ;
FH ) ( 3 out )
( R + R GG 75 43.532 10 ) ( R + R L
+
×
D
g
)
×
×
C = C + C g R = 4 10 − 12 + ( 1 10 − 12 × 2.217 10 − 3 × 947.368 = 6.100 pF
×
T iss rss m out
1 1
F = = = 348.655 MHz
H
π
×
×
×
×
C
2 R FH T 2 3.14 74.871 6.100 10 − 12
=
F == = 348.655 MHz
H
2.2.4.2 ก
)
#
*
A V (F H )

-

"
.
V

A V (F H ) o
E ก ,% 2.32 " ก
g
 R 


E = I R + I GG 
g i g i  + ω
C
  (1 J R GG T )  
 ( R + R ) + J R R C 
ω

g GG T 
E = I i  g GG 
g
C
 (1 J R+ ω GG T ) 


ω
+
C
E g (1 J R GG T )
I =
i
( R + R GG ) + J R R C
ω
g GG T
g
E R
g GG
V =
( R + R GG ) + J R R C
ω
g
g GG T
V = g VZ out
o
m
E g Z R
g m out GG
V =
o
ω
( R + R GG ) + J R R C
g
g GG T
V o g Z R
m out GG
A V (F H ) = − = −
E
C
g ( R + R GG ) J R Rω+ g GG T
g
1 R R
g GG
(
- ก X C = , R FH = ;
T
R FH ( R + R GG )
g
1 =
ω C R FH
T
1 ( R + R GG )
g
ω C = =
T
R FH R R
g GG
( R + R GG )
g
%
Cω T =
ก A V (F )
R R H
g GG
ก

ก
ก