Page 120 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

112
2.

V o V o V o
,
2.35 ก ,% 2.34 ! A V (F ) = − , A V (F ) = − , A V (F ) = −
Mid E i Mid E g L E g
V o
A V (F H ) = −
E
g
2I  V 
- .
ก ก (1.20) g = DSS  1− GS 
m
V P  V P 

* % I = 7.812 mA,V = − 4 V,V = − 1.108 V;
DSS P GS
×
×
2 7.812 10 − 3  − 1.108 
g = 1− = 2.824 mS
m  
− 4  − 4 
3
×
×
R R 2 10 × 1.5 10 3 857.142 Ω
D L
Z = R = = =
out out
( R + R L ) ( 2 10 + 1.5 10 3 )
×
3
×
D
V o ( − 3 ) 2.420
×
ก ก (2.53) A V (F Mid ) = − = − g Z = − 2.824 10 × 857.142 = −
m out
E
i
×
×
750 10 × 47 10 3
3
Z = R GG = = 44.228 kΩ
( 750 10 + 47 10 3 )
in
3
×
×
V o V o Z in
ก ก (2.53a) A V (F Mid ) = − E g = − E i × ( R + Z in )
g
×
V o ( − 3 ) 44.228 10 3
×
A V (F Mid ) = − = − 2.824 10 × 857.142 × ( 3 )
+
×
E g 75 44.228 10
V o
A = − = − (2.420 0.998× ) = − 2.415
V (F Mid )
E
g
V o
ก ก (2.57) A = − = 0.707A 45
V (F L ) V (F Mid )
E
g
A = − (0.707 2.415× ) = − 1.707 45
V (F L )
V o −
ก ก (2.58a) A V (F H ) = − = 0.707A V (F Mid ) 45
E
g
V o
A V (F H ) = − = − (0.707 2.415× ) − 45
E
g
V o
A V (F H ) = − E g = − 1.707 − 45
V o V o V o
= − −− −
== =
= − −− −
== =
= − −− −
== =
A V (F Mid ) = − −− − E i = − −− − 2.420, A V (F Mid ) = − −− − E g == = 2.415, A V (F L ) == = E g == = 1.707 45 ,
V o
== =
== =
A V (F H ) = − −− − E g = − −− − 1.707 − −− − 45 ;
ก

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