Page 122 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

114
2.

,
2.37 ก ,% 2.32 ! ) ก? % //0 "
%

2
×
=
×
×
- .
ก ก (2.71a) P R D = 2R D ( D ) ( 2 2 10 3 )( 4.083 10 − 3 ) 2 = 66.683 mW
I
R = 2 kΩ ± 5% ( - ก '"
1 W (125 mW)
D
8
2
×
ก ก (2.71b) P = 2R I ) = (2 560× )( 4.083 10 − 3 ) 2 = 18.671 mW
R S S ( D
R = 560 Ω ± 5% ( - ก '"
1 W (125 mW)
S
8
×
×
R
V DD G 2 20 47 10 3 1.179 V
ก ก (2.44) V = V = = =
R G 2 G ( R G 1 + R G 2 ) ( 750 10 + 47 10 3 )
3
×
×
=
−
V R G 1 = V DD − V R G 2 = 20 1.179 18.821 V
( 2 V R ) 2 ( 2 18.821 ) 2
ก ก (2.71c) P R = G 1 = = 0.944 mW
×
1
G
R G 1 750 10 3
R G 1 = 750 kΩ ± 5% ( - ก '"
1 W (125 mW)
8
( 2 V R ) 2 ( 2 1.179 ) 2
ก ก (2.71d) P = G 2 = = 0.05915 mW
R G 2 R G 2 47 10 3
×
R G 2 = 47 kΩ ± 5% ( - ก '"
1 W (125 mW)
8
" "
%

$
1 1
R = 2 kΩ ± 5% W, R = 560 Ω ± 5% W;
S
D
8 8
R G 1 = 750 kΩ ± 5% 1 W, R G 2 = 47 kΩ ± 5% 1 W;
8 8

2.2.5.11 ก

F*+,กH*#
%&&'
, กG )
# F

* , ก
//0 % ก & 2 (%
2.2.5.11.1 %

ก C , " ก ก
D
V C D = 2 V + V R S ) (2.72a)
( DS
2.2.5.11.2 %

ก C , " ก ก
S
V C S = 2 V S ) (2.72b)
( R
2.2.5.11.3 %

ก C , " ก ก
G

ก

ก
ก