Page 152 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

144

3.

1
ก !ก (3.26) C BT = 2 − C
′
b ep
π
L 11 ( 2 F ( R L 11 ) )
1 − 12
×
C BT = 2 − 209.919 10 = 53.171 nF
×
×
×
×
1.90 10 − 6 ( 2 3.14 500 10 3 )
1 1
ก !ก (3.27) C = =
CT 2 2
π
×
×
×
×
L 22 ( 2 F ( R L 22 ) ) 238 10 − 6 ( 2 3.14 500 10 3 )
C CT = 426.151 pF
" C = = = = 53.171 nF,C = = = = 426.151 pF;
BT CT
3.6.9 ก
$
"# ก1 $
&@.* $I

"
J
)
C BT = 53.171 nF +;
9 ! & D
C BT = (47 nF 5.6 nF ) . !(ก (52.6 nF
)
C CT = 426.151 pF +;
9 ! & D
C CT = (390 pF 39 pF ) . !(ก(429 pF

3.6.10 ก
$

'
B
W (L 11 )
B 9
' ( ' &
9 L & 9 r ,C % R ,
′
′
W (L 11 ) 11 b ep b ep g
r ก( กก r
&9 L
′
b e ′
11
b ep
r N 2 11
b e ′
r b ep =
′
N 2
21
C N 2 21
b e ′
ก !ก (3.25) C b ep = 2
′
N
11
1 (3.27a)
B W (L ) =
11 π + )
2 R ( C BT C b ep
′
R r ′
g b ep
, R =
R + r b ep
′
g
3.6.11 ก
$

'
B W (L 12 )

B W (L 12 ) 9
' ( ' &
9 L , & 9 R L (ab) % C CT (ab)
12
1
ก !ก (3.18) B W (L ) =
π
12
R
2 C CT (ab) L (ab)
C CT N 2 22
ก !ก (3.15) C CT (ab) = 2
N
12
2
R N 12
L
ก !ก (3.16) R =
L (ab) 2
N 32
ก

ก
ก