Page 163 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

155

3.

9 ก !ก (3.33) %& ! 9 & ก 9 9 I C (dc ) !ก (2.20)

, ก I = 4 mA
C
×
0.35V 0.35 12
ก !ก (2.24) R = CC = = 1,050 Ω
C
I × − 3
C 4 10
×
I C 4 10 − 3
I = β = 85 = 47.058 µA
B
F
×
0.15V 0.15 12
ก !ก (2.25) R = CC = = 444.775 Ω
E
( β + ) 1 I B 47.058 10 − 6 (85 1+ )
×
F
×
=
ก !ก (2.26) R TH = 15R = 15 444.775 6.671 kΩ
E
ก !ก (2.27) V TH = I R + V BE + (β + ) 1 I R
B TH
F
B E
×
×
V TH = ( 47.058 10 − 6 × 6.671 10 3 ) + 0.6
+ ( 86 47.058 10 − 6 × 444.775 )
×
×
V = 2.692 V
TH
×
×
V CC TH 12 6.671 10 3 29.736 kΩ
R
ก !ก (2.28) R = = =
B 1
V TH 2.692
×
×
V CC TH 12 6.671 10 3 8.6 kΩ
R
R = = =
B 2 − ) (12 2.692− )
V
( CC V TH
1
ก !ก (2.29) C =
B
π
2 R F
FLCB ( L C B )
Ω
, R FLCB = X C B = X C E = X C C = 0.5 , F ( L C B ) = F ( L C E ) = F ( L C C ) = 5.5 MHz;
1
C = = 0.0579 µF
B 6
×
×
×
×
2 3.14 0.5 5.5 10
C = C = C = 0.0579 µF
E
C
B
" ก +
9 R % C +;
9 ! & D
! "
&
1
R = 1, 050 Ω +;
9 ! & D
R = 1 kΩ ± 5% W
C C
8
1
R = 444.775 Ω +;
9 ! & D
R = 430 Ω ± 5% W
E E
8
1 W
R = 29.736 kΩ +;
9 ! & D
R = 30 kΩ ± 5%
B 1 B 1
8
1 W
R = 8.6 kΩ +;
9 ! & D
R = 9.1 kΩ ± 5%
B 2 B 2
8
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
B B
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
E
E
C = 0.0579 µF +;
9 ! & D
C = 0.056 µF 50 V
C
C
ก

ก
ก