Page 165 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

157

3.

1
F = = 97.11 MHz
H
×
×
×
×
2 3.14 66.397 24.696 10 − 12
=
" F == = 97.11 MHz .# ! 9 ก 9 5.5 MHz 9
.( & ' ! 8 5.5 MHz
H
ก
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+ A V (F R )
)
V o (0.5 g Z r R
′
m out b e BB
ก !ก (3.31) A = − = −
V (F R ) + + + + )
E
r
i 1 R CF 2 ( R BB r bb′ r b e ′ ) R BB ( bb′ r b e ′
×
×
×
×
×
0.5 164.902 10 − 3 × 69.767 515.457 6.982 10 3
A V (F R ) = − ( 3 ) 3 )
×
+
×
75 6.982 10 + 2 515.457 + 6.982 10 (2 515.457+
×
20.702 10 6
A V (F R ) = − ( 562.459 10 + 3.612 10 6 ) = − 4.959
×
×
3
V o
= − −− −
= − −− −
" A V (F R ) == = E i 1 == = 4.959

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