Page 22 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

14
1. !!" # $
%&

1.1.3 ก4 ' #

ก %& %

! 1.3 '0ก1 ( ))2 / !! ก "

'0ก1 ( ))2 +W $" , 25 C

'0ก1 ( &
/ , 05'0ก1 ! * !0 +
0 ก'0, ก ( ! I = 60 µA V 20 - - V

(DC Reverse Voltage) R R
ก ( ! ก'0, V = 16 V I - - 30 µA
(DC Reverse Current) R R

0 / (/ 0 + I = 10 mA, T = 25 C; - - 220

A
F
(Instantaneous Forward Voltage) I = 100 mA, T = 25 C; V - - 300 mV

(Pulse test 300 ms pulse width, 1% F A F
duty cycle) I = 10 mA, T = 100 C; - - 180

A
F
& ' )pq !0 ก'0, / " I = I = 100 mA; t - 32 -
(Diode Reverse Recovery Time) F R rr ns
- " V = 0, f = 1 MHz; C - 0.88 1 pF
(Diode Capacitance) R D
+ &+! !0 &'/ ! & . ก!0 ก j$,

1.1.3.1 % ก ก

(V
)
R
& & ก0, +0 / 1.1.1.1 0 1.3

A
I R = 60 µA
V R =20 V
D 1

1.3 ก , ก'0, '(ก 0 V / !! ก "
0
R

- ก! 1.3 V = 20 V
R
- ก 1.4 '(& :-
0

− & ก ) T = 25 C,V = 20 V,I = 60 µA;

R
R
A
− & ก ) T = 100 C,V = 20 V,I ≈ 3000 µA;

R
R
A
− ก & ' ' / +W $-( 80 ! ก0,ก ( I
R
ก

ก
ก