Page 24 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

16
1. !!" # $
%&

)
1.1.3.3 # ' ' % -. / (V F
0 / (/ 0 + & . 0 0 / (!ก " / (

0, , + " ก 2 0' / 300 ms 0s-0ก + 1% (Duty Cycle)

1000

T = 25 C

A
T = 100 C

A
-Forward Current (mA)
100

A
F 10 T = − 50 C
I
I = 10 mA,V = 220 mV;
F
F

1
0 100 200 300 400 500

1.6 0 0 j (+ ก ( I ก0, 0 V
F
F
- ก! 1.3 '(& &ก ก0,V 0 :-
F
− V = 220 mV,I = 10 mA,T = 25 C;

F
A
F
− V = 300 mV, I = 100 mA,T = 25 C;

F F A
− V = 180 mV,I = 100 mA,T = 100 C;

A
F
F
0
- ก 1.6 '(& :-
− & ก ) T = 25 C,I = 10 mA,V = 220 mV;

F
A
F
− & ก ) T = 100 C,I = 10 mA,V = 100 mV;

A F F
− & ก )T = − 50 C,I = 10 mA,V = 300 mV;

F
F
A
1.1.3.4 78
ก ' %& % (t
)
rr
& ' )pq !0 ก'0, / " & . & ' ก ( +'8 "
0
$
/ ( 0, ก'0, +
& . & ' 7 &'tก! $ ( - ก ก7 !0 * $ ก'0,
t
ก7 !0 * $ & " * -( t ! * ก
rr
- ก! 1.3 t = 32 ns
rr
ก

ก
ก