Page 243 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

235
6.

1 1
ก !ก (6.15) B W in = = = 1.5 GHz
π
×
×
×
×
2 R bwi ip ( 2 3.14 70.993 1.495 10 − 12 )
C
3
×
R out L 1 10 × 75
R
ก !ก (6.16) R bwo = = = 69.767 Ω
×
3
R
( out + R L ) ( 1 10 + 75 )
1 1
ก !ก (6.17) B W out = = = 4.564 GHz
π
×
×
×
×
C
2 R bwo ce ( 2 3.14 69.767 0.5 10 − 12 )

R = == = 1.329 k , C =Ω Ω ip = = = 1.495 pF, L mi = = = = 34.613 nH, L mo = = = = 103.493 nH, B W in = = = = 1.5 GHz,
Ω Ω
ip
2
B W out = == = 4.564 GHz 42 !'" 4 ก B W in = == = 1.5 GHz
ก 6; L L ก ก ( (

mi mo

( " !7' # (S กN : ;$ !
6.1.2.4 ก
$ -) (! "

( C ก C ' ( " L 5 L′ 6 # 4' 6.9
ipp
ip
mi
mi
R R
ip S
ก !ก (6.14) R bwi = ( ip R S ) = )
R
R +
( ip R S
1
ก !ก (6.15) B W in =
2 Rπ bwi ip
C
$ ก C = C ipx
ip
1
B W in =
π
2 R bwi ipx
C
ก
" C ipx
1
% C ipx = (6.18)
π
2 R bwi (B W in )

% กN :4' ก C 7#ก ! " 6
!
ip
C = C − C (6.19)
ipp ipx ip
!$ ( C ipp C ip ) :

2 ' ( ! " L 6
!
mi
1
ก !ก (6.11) L mi = (4' C 7#ก ' ( 5 ( C ipp C ip )
ip
2
( 2 Fπ R ) C ip
1
% L′ = (6.20)
mi
2
π
( 2 F R ) ( C + C ipp )
ip
ก

ก
ก