Page 244 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

236
6.

Z in Z out

E S L mi R ip C ip C ce R out L mo

Z Z
in out

L′ R C C R L
E S mi C ipp ip ip ce out mo

2
# 4' 6.9 ก " 42 (6; L′ C
mi
ipp

! 6.4 ก ( 4' 6.3 ก 42 B ก 1.5 GHz6

$ 1'(
2
W in
50 MHz (" !7'

2" !

2
"# $ ก 4 6
" 42 ( C ก C
ip
ipx
×
3
R R 1.329 10 × 75
ip S
=
ก !ก (6.14) R bwi = ) ( 3 = 70.993 Ω
R +
×
( ip R S 1.329 10 + 75 )
1
ก !ก (6.18) C ipx =
π
2 R bwi (B W in )
(4' C "$ " " ! I ( ก 6
! 4 4' C
:
ipx
ip
B = 50 MHz
W in
1 44.859 pF
C = =
ipx 6
×
×
×
×
2 3.14 70.993 50 10
:
% กN 4' ก C 7#ก ! " 6
!
ip
ก !ก (6.19) C ipp = C ipx − C
ip
:

(4' C "$ " " ! 4' ก C
ipp ip
C ipp = ( 44.859 10 − 12 − 1.495 10 − 12 ) = 43.364 pF
×
×
1
ก !ก (6.20) L′ =
mi
2
C +
π
(2 F R ) ( ip C ipp )
(4' L′ "$ " " !
' ( 6
! 4' ก C ipp
mi
ก

ก
ก