Page 74 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

66
2.

2
V I R ( g r R ) R L Z
′
m b e C
P = o × L = × in (2.12a)
G 2
E I ) ( R + )
g b Z i ( R + R L g Z in
C
2
g r R
V I R ( m b e C ) R L
′
P = o × L = (2.12b)
G
E I R + ) 2
i b Z i ( C R L
,
2.4 ก ,% 2.1 , P (dB) ( - '"ก ! E E
G i g
2
V I R ( g r R ) R L
′
m b e C
- .
ก ก (2.12b) P = o × L =
G
E I R + ) 2
i b Z i ( C R L
V I R
=
P = o × L = 11.812 93.023 1, 098.787
×
G E i I b
P = 10 log 1, 098.787 = 30.409 dB
10
G
2
V I R ( g r R ) R L Z
′
m b e C
ก ก (2.12a) P = o × L = × in
G 2
E g I b Z i ( R + R L ) ( R + Z in )
g
C
V I R 547.521
P = o × L = 11.812 93.023× )
×
G
+
E g I b (75 547.521
V I R
P = o × L = 11.812 93.023 0.879
×
×
G
E I
g b
V I R
P = o × L = 965.834
G E g I b
P = 10 log 965.834 = 29.849 dB
G 10
"
"
( - '" E P = == = 30.409 dB ( - '" E P = == = 29.849 dB
i G g G
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