Page 76 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

68
2.

R BB (r bb′ + r b e ′ )

$
R FLCB = R +
g
( R BB + r bb′ + r b e ′ )

,
2.5 ก ,% 2.1 , F ( L C B )
1
- .
ก ก (2.13) F ( L C ) =
π
B 2 R FLCB B
C
R BB (r bb′ + r b e ′ ) 7,500 ( 2 588.64+ )
* % R = R + = 75 + = 622.521 Ω
FLCB g )
( R BB + r bb′ + r b e ′ (7,500 2 588.64+ + )
1 = 1
=
F ( L C B ) 2 R FLCB B 2 3.14 622.521 240 10 − 12
π
×
×
×
×
C
F = 1.065 MHz
( L C B )
F ( L C B ) = == = 1.065 MHz
2.1.3.2 ก
)
#
*
F ( L C )
E
ก ,% 2.10 ( - E
(% ก ! F ( L C E ) # (,5

"
%
g
C ! ) % & & ( % ." X (% ก ! R FLCE
, F ( L C E ) " ก ก
C
E
E
X C E = R FLCE
1
(
- ก X C E = 2 F ( L CE ) E
π
C
1 = R
"
π
2 F C FLCE
( L CE ) E
1 (2.14)

$
F ( L C E ) =
π
2 R
FLCE C E
r bb′
B b′ C
I b I c
r V g V
R g b e ′ b e ′ m b e ′
R BB
E g R OUT
E
R E
C E
R FLCE

,% 2.10 , F
( L C E )
"
# (,5
"
%
% (
C (3- .

ก , R
FLCE E
, R R ."

& & ( ก (,5
r bb′ r b e ′ R g
# " r bb′ , r b e ′ g BB , ,
(β + 1 ) (β + ) 1 (β + ) 1
o
o
o
ก

ก
ก