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                                        1          1     3              1        1     3
                                   x −      <    − x +       OR     x −     <      x −
                                        4          2     4              4        2     4
                                        3                                1        1
                                          x < 1              OR           x < −
                                        2                                2        2
                                                2
                                          x <                OR           x < −1
                                                3
                         The solution set is   {−∞, −1}

                                 1
                     2. Solve          < 6 and express the solution using the interval notation.
                              |2x − 1|
                                                   1
                           Not For Sale - Veeraragavan C S veeraa1729@gmail.com
                        Solution: Given |2x − 1| >
                                                   6
                                     1                      1
                        (2x − 1) >       OR (2x − 1) < −
                                     6                      6
                                     7                    5
                              2x >       OR        2x <
                                     6                    6
                                      7                    5
                               x >       OR          x <
                                     12                   12


                                      5         7
                        x ∈    −∞,         ∪      , ∞
                                     12        12
                     3. Solve −3|x| + 5 ≤ −2 and graph the solution set in a number line.
                        Solution:
                        −3|x| ≤ −7

                                   7
                           |x| ≥
                                   3
                                   7               7
                             x ≥       OR x ≤ −
                                   3               3

                                       7              7
                        x ∈    −∞, −       OR x ∈      , ∞
                                       3              3
                     4. Solve 2|x + 1| − 6 ≤ 7 and graph the solution set in a number line.
                        Solution:
                                    13
                         |x + 1| ≤
                                     2
                                    13                    13
                        (x + 1) ≤       (or) (x + 1) ≥ −
                                     2                     2
                                    11                    15
                              x ≤       (or)       x ≥ −
                                     2                     2

                                 15 11
                        x ∈    −    ,
                                  2   2
                              1
                     5. Solve |10x − 2| < 1.
                              5
                        Solution:
                        |10x − 2| < 5
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