Page 118 - HOW TO PROVE IT: A Structured Approach, Second Edition
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                                   104                         Proofs
                                     The goal is also a conditional statement, so we assume the antecedent and
                                   set the consequent as our new goal:
                                                  Givens                      Goal
                                               P → (Q → R)                  P →¬Q
                                               ¬R
                                   We can also now write a little bit of the proof:

                                       Suppose ¬R.
                                         [Proof of P →¬Q goes here.]
                                       Therefore ¬R → (P →¬Q).

                                     We still can’t do anything with the givens, but the goal is another conditional,
                                   so we use the same strategy again:
                                                  Givens                      Goal
                                               P → (Q → R)                     ¬Q
                                               ¬R
                                               P
                                   Now the proof looks like this:

                                       Suppose ¬R.
                                         Suppose P.
                                           [Proof of ¬Q goes here.]
                                         Therefore P →¬Q.
                                       Therefore ¬R → (P →¬Q).
                                     We’ve been watching for our chance to use our first given by applying
                                   either modus ponens or modus tollens, and now we can do it. Since we know
                                   P → (Q → R) and P, by modus ponens we can infer Q → R. Any conclusion
                                   inferred from the givens can be added to the givens column:
                                                  Givens                      Goal
                                               P → (Q → R)                     ¬Q
                                               ¬R
                                               P
                                               Q → R
                                   We also add one more line to the proof:
                                       Suppose ¬R.
                                         Suppose P.
                                           Since P and P → (Q → R), it follows that Q → R.
                                           [Proof of ¬Q goes here.]
                                         Therefore P →¬Q.
                                       Therefore ¬R → (P →¬Q).
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