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Mari Berlatih





          Contoh 1. Calculating from pH [H 3O ] or [OH ]
                                        +
                                                -
          Calculate the pH of each of the following solutions at 25 C  and  indicate whether the
                                                         0
          solution is acidic or basic.
          (a) [H 3O] = 1.8 X 10 M      (b) [OH ] = 1.3 x 10
                                                -2
                          -4
                                      -

          Solution
           (a) To calculate pH, substitute the given  pH = -log[H 3O ]
                                                           +
           [H 3O ]  into  the  pH  equation.  Since  pH        = -log(1.8 x 10-4 )
               +
           <7, this solution is acidic.              = (-3.74)
                                                     = 3.74 (acidic)
                                           -
           (b) First use K w to find [H 3O] from [OH ]  [H 3O ] = K w = 1.0 x 10 -14
                                                   +
                                               [H 3O ] (1.3 x 10 ) = 1.0 x 10-14
                                                   +
                                                            -2
            Then  substitute  [H 3O]  into  the  pH  [H 3O ] = 1.0 x 10 = 7.7 x 10 -13  M
                                                   +
                                                             14
           expression to find pH.                            1.3 x 10
                                                            -2
                                                            +
                                               pH = - log [H 3O ]
           Since pH >7, this solution is basic.         = - log (7.7 x 10 )
                                                               -13
                                                     = - (-12.11)
                                                     = 12.11 (basic)













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