Page 20 - Electrostatics-11
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© GC Shiba
        Applications of Gauss Theorem:

               In actual practice, we can never have a point charge, rather we do have

        charge bodies having different shapes. Coulomb law cannot be applied directly to
        calculate the electric field having different shapes of charge bodies. In such
        situations, Gauss theorem is applicable.


        1) Electric intensity inside a charged conducting solid sphere
               Consider a charge conducting sphere of radius R

        having a charge +Q. We are interested to find the electric
        intensity at point P inside a charged sphere. Let us draw a
        concentric sphere of radius r through point P. This sphere is                         P

        called a Gaussian sphere.
        By symmetry, electric intensity would be the same at all
        points on the surface of a Gaussian sphere. Electric flux from

        the charged sphere is radially outward as shown in the
        figure.
        Now, electric flux passing through the gaussian surface is

                                                                        ℎ        
                                                   =
                                                               ∈ 0

                                                   =E × A
                                            or,  E × A = 0 ( since no charge is enclosed by
                                                                         gaussian surface)

                                                   E = 0
        Hence, there is no electric field inside the charged sphere.


        2) Electric intensity outside a charged conducting sphere

               Consider a charge conducting sphere of radius R

        having a charge +Q. We are interested to find the electric
        intensity at point P outside a charged sphere. Let us draw
        a concentric sphere of radius r through point P. This
        sphere is called a Gaussian sphere.

        By symmetry, electric intensity would be the  same at all
        points on the surface of a Gaussian sphere. Electric flux
        from the charged sphere is radially outward as shown in

        the figure.
        Now, electric flux passing through the gaussian surface is





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