Page 19 - Electrostatics-11
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© GC Shiba
        Gauss Theorem:

               Statement:  The  total  electric  flux  passing  through  the  closed  surface  of
                                                1
        arbitrary  shape  is  equal  to               times  the  enclosed  charge  where  ∈   is  the
                                                ∈ 0                                                   0
        permittivity of a free space.

                                                                        ℎ        
                                      ∴        =
                                                                  ∈ 0


        Let +Q charge enclosed by an arbitrary shape surface is shown in figure.



























        Total electric flux through this surface is


                                                                        ℎ        
                                                  =
                                                               ∈ 0
                                                                   
                                                     ∴        =
                                                                 ∈ 0
        Proof for spherical surface:
               Consider a +Q charge at the center of a sphere of radius r. The electric
        intensity at the surface of sphere is

                                                                 
                                                       =
                                                           4        2
                                                                0
                                                             1
                                                     =         Where    = 4     =                                  ℎ      
                                                                                2
                                                              
                                                           0
                                                                 
                                            or,  E × A =
                                                               ∈ 0
                                                                
                                                   ∴     =
                                                             ∈ 0



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