Page 8 - Pra U STPM 2022 Penggal 1 - Mathematics (T)
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Mathematics Term 1  STPM  Chapter 1 Functions


                                                      y

                                              f                                                           1
                                                                  g


                                   x                                            z
                                                        g   f
                                                         °
                                                      Figure 1.4
            For example, if
                         f : x ↦ x – 2 and g : x ↦ 3x,
            i.e.         f(x)  = x – 2 and g(x) = 3x,
            then       g[f(x)]  = 3f(x)
                              = 3(x – 2)
            Hence,    g   f : x  ↦ 3(x – 2)
                       °
            For example, if x = 5,
                      f(5) = 5 – 2 = 3
                      g(3) = 3(3) = 9
            i.e.      g[f(5)] = g(3) = 9


                                                      3

                                              f
                                                                  g

                                   5                                            9
                                                        g   f
                                                         °
                                                      Figure 1.5

                 Example 3

                      2
              If f(x) = x  and g(x) = x + 1, find
              (a)  f   g(x)                                        (b)  g   f(x)
                   °
                                                                         °
              (c)  f   f(x)                                        (d)  g   g(x)
                                                                         °
                   °
              Solution:           (a)  f   g(x)  = f[g(x)]         (b)  g   f(x)  = g[f(x)]
                                                                         °
                                       °
                                                                                   2
                                             = f(x + 1)                       = g(x )
                                             = (x + 1) 2                      = x  + 1
                                                                                 2
                                  (c)  f   f(x)  = f[f(x)]         (d)  g   g(x)  = g[g(x)]
                                                                         °
                                       °
                                             = f(x )                          = g(x + 1)
                                                 2
                                             = (x )                           = (x + 1) + 1
                                                2 2
                                             = x 4                            = x + 2
            Note:   1.  f   g ≠ g   f, from (a) and (b).
                       °
                              °
                  2.  f[g(x)] ≠ f(x) · g(x) since f[g(x)] = (x + 1)  whereas f(x) · g(x) = x (x + 1).
                                                                             2
                                                         2
                                                                                                    5





     01a STPM Math T T1.indd   5                                                                    3/28/18   4:20 PM
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